PHP and SQL help

[Trevor]

I am trying to get a echo in PHP to print in a table i have created on the same page. This is my current coding

 

<?php
$con = mysql_connect("localhost","****","****");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("****", $con);

$result = mysql_query("SELECT * FROM members
WHERE member_msisdn='$slusername'");
echo "<table border='1'>
<tr>
<th>Membership</th>
<th>Number</th>
<th>Registration Date</th>
<th>End Date</th>
<th>Copy of ID</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<td><center>" . $row['member_id'] . "</td>";
echo "<td><font color=blue>" . $row['member_msisdn'] . "</td>";
echo "<td><center>" . $row['asdate'] . "</td>";
echo "<td><center>" . $row['aedate'] . "</td>";
echo "<td><center>" . $row['attid'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysql_close($con);
?></div>
<div class="Notes"><strong><br>
Emergency Contact Numbers:</strong><br>
<?php
$con = mysql_connect("localhost","****","****");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}

mysql_select_db("****", $con);

$result = mysql_query("SELECT * FROM members a INNER JOIN recipients b ON a.member_id =
b.member_id WHERE member_msisdn=$slusername");
echo "<table border='1'>
<tr>
<th>Number</th>
<th>Name</th>
<th>Surname</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<td><font color=blue>" . $row['recipient_msisdn'] . "</td>";
echo "<td>" . $row['recipient_name'] . "</td>";
echo "<td>" . $row['recipient_surname'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysql_close($con);
?>
</div>
<p>
<label for="member_id"></label>
<input type="text" name="member_id" id="member_id"> // here i need the member_id of members to be printed so i can have it entered into another table on same sql DB
</p>
<p><br>
</p>
</div></td>

 

Basically i need the to print or past it in the input that it will use it later on a different table in the SQL DB

[davidannis]

I'm not understanding the question but I know that you need a <form action="somethingToDoWithTheInput.php" method="POST"> before the input and a submit and /form after it. If you wnat to prepopulate the input you need to do something like:

<input type="text" name="member_id" value="<?php echo $mydata['name'];?>"  id="member_id">

 

Does that help?

David