sending radiobutton value via $_POST

[learningPHP1]

Hello,

 

Problem area: radio buttons in a user form.

Initially the radio buttons are unchecked which is fine for what i need

If one of the radio button is selected the process.php scripts recives the value via $_POST, which works fine.

if the radio button isn't selected nothing is sent via $_POST. This is where the problem is....

 

I need:

f the user forgets to select the radio button noting is sent via $_POST. If nothing is sent via $_POST  the process.php

script is unable to verify the wheather the user made a selection or not.

 

print_r($_POST) ==>Array ( [name] => => [birthday] => [formSubmit] => Submit )

radiobutton doesn't appear. how can in include the radio button as part of the $_POST  so that process.php can process the selection weather its empty or not?

 

 

 

form.php

<form name="formprocess" method="POST" action="process.php"> 
    Name: <input type="text" name="name" value="<?php echo $name; ?>" > <br /> 
    eMail: <input type="text" name="email" value="<?php echo $email; ?>" > <br /> 
    Birthday:<input type="text" name="birthday" value="<?php echo $birthday; ?>" /><br /> 
    <br /> 
    <p> <input type="radio" name="radiobutton" value="1" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 1) ?  'checked':''; ?>> OptionOne </p> 
    <p> <input type="radio" name="radiobutton" value="2" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 2) ?  'checked':''; ?>> OptionTwo </p> 
    <p> <input type="radio" name="radiobutton" value="3" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 3) ?  'checked':''; ?>> OptionThree</p> 
     
    <input type="submit" name="formSubmit" value="Submit"> 
</form> 

 

process.php

$allowedFields = array(
	'name',
	'email',
	'birthday',
	'radiobutton',
);

$requiredFields = array(
	'name',
	'email',
	'radiobutton',
);
echo 'radiobutton1: '. $_POST['radiobutton'];
echo '<br />';
 print_r($_POST);
//loop through the POST array

$fieldErrors = array();
foreach($_POST as $key=>$value)
{	// allowed fields
	if(in_array($key, $allowedFields))
	{	$$key = $value;
		// required field?
		if(in_array($key, $requiredFields) && $value == '')
		{	$fieldErrors[] = "The field $key is required."; 
		}
	}	
}

 

[denno020]

You could use isset() to find out if the $_POST variable for the radio buttons are set. Inside that if, have all your radio button processing, so that will only run if a radio button was set.

 

Denno

[Barand]

Another technique is to put a hidden field (with the same name as the radio buttons and zero value) before the button group. If no button is selected the hidden field value is sent.

 

<input type='hidden' name='radiobutton' value='0' />
<p> <input type="radio" name="radiobutton" value="1" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 1) ? 'checked':''; ?>> OptionOne </p>
<p> <input type="radio" name="radiobutton" value="2" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 2) ? 'checked':''; ?>> OptionTwo </p>
<p> <input type="radio" name="radiobutton" value="3" <?php echo (isset($_POST['radiobutton']) && $_POST['radiobutton'] == 3) ? 'checked':''; ?>> OptionThree</p>

[learningPHP1]

Thanks everybody, I greatly appreciate your post replies back.

 

I ended up going with barands answer. I added the hidden input field and it seem to have fixed the issue in my script..

I did change one thing in Brands answer i changed the value='0' to value=''. this gave me what i needed..

 

again thanks for the help.