PHP GD immagecopy problem

[dvwyngaa]

Hi,

I want to add an icon (16x16px), black and white in .png format to an existing .png file with bunch of text. What I get is a black square on top of the image with the text. Neither of the images have any transparent background. The code I used is as follows:

<?php
$source=imagecreatefrompng("message.png");
$img_get=imagecreatefrompng("smiley1.png");

imagecopy($source,$img_get, 5, 12, 20, 20, 20, 20);

header('Content-Type: image/png');
imagepng($source);
imagedestroy($source);
imagedestroy($img_get);
?>

Any ideas why this doing this, the black squared instead of the actual icon picture (see attached screenshot)? Any suggestions welcome!

Regards,

Dawid

 

[jazzman1]

Not sure where could be the problem but can you put down that on the top of the script:

ini_set("display_errors", true);
error_reporting(-1)

[dvwyngaa]

jazzman1,

 

Thanks, I did that, but the script doesn't give any errors. I can view both the files (.png's) seperately, but as soon as I use imagecopy or imagecopymerge, the icon appears as a black block on top of the other.

 

Dawid

[mac_gyver]

what dimensions are the smiley1.png image? it may be that you are just copying a small back section of it onto the other image.

[jazzman1]

I think you should create a new canvas and then to put this two images all together inside it.

 

I've made a quick test and it's work with jpeg:

<?php
ini_set("display_errors", true);
error_reporting(-1);

$canvas = imagecreatetruecolor(200, 200);

$img1 = imagecreatefromjpeg('images/centos.jpeg');
$img2 = imagecreatefromjpeg('images/redhat.jpeg');

imagecopy($canvas, $img1, 0, 20, 0, 0, 100, 100);
imagecopy($canvas, $img2, 0, 10, 0, 0, 100, 100);

header('Content-Type: image/jpg');
// ... copy additional source images to the canvas as needed
imagejpeg($canvas);

PS. I am not familiar with GD

[Eiseth]

Change this

imagecopy($source,$img_get, 5, 12, 20, 20, 20, 20);

to this 

// because 0, 0 means the copy will start from the top left of the smiley face
// putting 20x20 from a 16x16 picture doesn't make any sense
imagecopy($source,$img_get, 5, 12, 0, 0, 16, 16);