Having trouble with sorted data

[Xana]

CREATE TABLE `events` (
 `id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'id',
 `name` varchar(60) NOT NULL COMMENT 'name',
 `company` varchar(60) NOT NULL COMMENT 'company',
 `datetime` datetime NOT NULL COMMENT 'datetime',
 `url` varchar(160) NOT NULL COMMENT 'announcement pagelink',
 `anncement_pg` varchar(160) NOT NULL COMMENT 'date the event was announced',
 `anncement_date` date NOT NULL,
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=11 DEFAULT CHARSET=utf8

 

 

I'm trying to reproduce these results in a tabular layout that is ordered by ascending dates(datetime).

 

But, I want the first two entries to be the last two recent events, in other words, the last two results in the order before now(), but once I get those results, they are still in descending order. Although they are the two that I need from the table.

SELECT * FROM events WHERE (datetime < NOW()) ORDER BY datetime DESC LIMIT 2

 

This is far as I could get without producing errors. This works for my purposes, except what comes back is descending order, but it's the correct results.

How do I order something so that I can get the last two results of that query, but then order it so that it comes back in the array as how I want it to be printed in the list? Or is there an easier way?

 

Edit: MySQL server is 5.1.56

Edited May 25, 2013 by Xana

[kicken]

Rather than try and get a query to give you exactly what you want, which I'm not sure is possible as the requirements are a bit odd, just order the query in ascending order and then before printing the list, move the last two items to the top. For example, in PHP:

$data = $db->query('SELECT * FROM events WHERE (datetime < NOW()) ORDER BY datetime')->fetchAll();
$last2 = array_splice($data, -2); //remove the last two
array_unshift($data, $last2[1], $last2[0]); //add them back to the top of the array.