Digiboy Posted June 3, 2013 Share Posted June 3, 2013 hi guys, Im trying to calculate number of days and time passed a time stamp but I always get 0 do you know why? Am I making funny mistake again? date_bought= "2013-06-02 15:57:04"; $add_days = 7; $date= date('Y-m-d',strtotime( $date_bought) + (24*3600*$add_days)); $result_date= $date - $date_bought; echo"$result_date"; Quote Link to comment Share on other sites More sharing options...
DaveyK Posted June 3, 2013 Share Posted June 3, 2013 $result_date= $date - $date_bought; You cant do this. You are trying to substract two strings. Also, even if you got this to work, with the current math the answer will always be 7 days. Quote Link to comment Share on other sites More sharing options...
taquitosensei Posted June 3, 2013 Share Posted June 3, 2013 This will substract two dates and give you the difference in hours/minutes. Like DaveyK said if you add 7 days to a timestamp then subtract the original timestamp from it. You will always get exactly 7 days. $diff = strtotime($timestamp2) - strtotime($timestamp1); $hours = floor($diff / 3600); $diff %= 3600; $minutes = floor($diff / 60); hi guys, Im trying to calculate number of days and time passed a time stamp but I always get 0 do you know why? Am I making funny mistake again? date_bought= "2013-06-02 15:57:04"; $add_days = 7; $date= date('Y-m-d',strtotime( $date_bought) + (24*3600*$add_days)); $result_date= $date - $date_bought; echo"$result_date"; Quote Link to comment Share on other sites More sharing options...
AbraCadaver Posted June 3, 2013 Share Posted June 3, 2013 You really shouldn't use math to calculate these things or you get into daylight savings time troubles: $date = date('Y-m-d', strtotime("+ $add_days days", strtotime($date_bought))); Quote Link to comment Share on other sites More sharing options...
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