PHP form with IF statement

[wizzy886]

I am currently trying to make a simple math sort of form where I can define two main variables that I then subtract to work out a theoretical profit. I may try and plug in a rand() into the income and costs but for now I kept it simple. I am struggling to make the final If statement work. It does not know that the variable is 5 9I have put a comment where I am referring to).

 

All help will be greatful, thanks.

 

profit_calc.php

<?php
	$pnd = "&pound";

	$income= 10;
	echo '<p>Income = ' .$pnd.$income. '</p>';

	$costs= 5;
	echo '<p>Costs = ' .$pnd.$costs. '</p>';

	$profits=$income-$costs;
	echo '<p>Profit = ' .$pnd.$profits. '</p>';


		if (!empty($_REQUEST['answer'])) {
			$_REQUEST['answer'] = $answer;

/* What Do I Do Here */
				if ($answer == $profits) {
					echo "Correct.";
				} else {
					echo "Incorrect.";
				}
		} else {
			$answer = NULL;
			echo "You did not enter anything.";
		}

?>

<form action="profit_calc.php">
	<p><input type="text" name="answer"></p>
		<p><input type="submit" name="submit" value="submit"></p>
</form>

[Irate]

Use $_POST['answer'] and set <form action="profit_calc.php" method="POST">

[Barand]

Couple of other errors

 

$pnd = "&pound";  - there should be a ; after pound

$_REQUEST['answer'] = $answer;

should be

$answer = $_REQUEST['answer'];

[wizzy886]

Thank you a lot. I believe it is working fully.