phpgoal Posted June 14, 2013 Share Posted June 14, 2013 Hello, If month = 4, I want to see car1 picture. If month = 5, i want to see car3 picture. I am stuck with car1 picture. How can I do it? <head>..............onSelect: function( selectedDate ) { if(this.id == 'from'){ var dateMin = $('#from').datepicker("getDate"); var rMin = new Date(dateMin.getFullYear(), dateMin.getMonth(),dateMin.getDate() + 0); alert (rMin.getMonth()); if(rMin.getMonth() == 4){ var image1=new Image() image1.src="car1.jpg" } if(rMin.getMonth() ==5){ var image2=new Image() image2.src="car3.jpg" } } } }); </script></head> <body> <div class="demo"> <label for="from">From</label><input type="text" id="from" name="from"/> <label for="pics">pics</label><input type="image" id="pics" name="pics" src="car1.jpg" alt="Submit" width="48" height="48"> ............... Link to comment https://forums.phpfreaks.com/topic/279155-datepicker-picture-display/ Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.