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HELP! Email activation function bug

codingdreamer

By codingdreamer
in Applications

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codingdreamer Newbie

codingdreamer

Posted
Posted

Hello All,

 

I'm having difficulty figuring out why my activation page isn't responding correctly. When I click on a link to activate my test account, the function takes me to the site with the right information populated in the text box; however, when I go to submit, it triggers an else function instead of the if function (to activate the account). I've tried changing   $getuser = $_GET['user'] to $_POST but no luck thus far. Any help/insights would be greatly appreciated! Thanks.

 

 

 

When I click on the link to activate I get this (example screenshot):

 

Username: test

Code: afcadjijckack

 

[Activate button]

 

 

Upon clicking on the 'Activate' button, I get this (example screenshot):

 

You must enter your code

 

Username: afcadjijckack

Code: (blank)

 

[Activate button]

 

 

Here's my code:

<?php 
error_reporting (E_ALL^E_NOTICE);
session_start();
$userid = $_SESSION['userid'];
$username = $_SESSION['username'];
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
	<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
	<title>Activate Your Account</title>
</head>
<body>

<?php 

	$getuser = $_GET['user'];
	$getcode = $_GET['code'];
	
	
	if ( $_POST['activatebtn'] ) {
		$getuser = $_POST['user'];
		$getcode = $_POST['code'];
		
		if ($getuser){
			if ($getcode){
				require("./connect.php");
				
				$query = mysql_query("SELECT * FROM users WHERE username='$getuser'");
				$numrows = mysql_num_rows($query);
				if ($numrows == 1){
					$row = mysql_fetch_assoc($query);
					$dbcode = $row['code'];
					$dbactive = $row['active'];
					
					if($dbactive == 0){
						if($dbcode == $getcode) {
							mysql_query("UPDATE users SET active='1' WHERE username='$getuser'" );
							$query = mysql_query("SELECT * FROM users WHERE username='$getuser' AND active='1' ");
							$numrows = mysql_num_rows($query);
							
							if($numrows == 1) {
								$errormsg = "Your account has been activated. You may now login.";
								$getuser = "";
								$getcode = "";
							}
							else
								$errormsg = "An error has occured. Your account was not activated.";
						}
						else
							$errormsg = "your code is incorrect.";
					
					}
					else
						$errormsg = "This account is already active.";
				
				}
				else
					$errormsg = "The username you entered was not found.";
				
				mysql_close();
			}
			else
				$errormsg = "You must enter your code.";
		
		}
		else
			$errormsg = "You must enter your username.";
	}
	else
		$errormsg= "";
	
	
		echo "<form action='./activate.php' method='post'>
		<table>
		<tr>
			<td>$errormsg</td>
		</tr>
		<tr>
			<td>Username:</td>
			<td><input type='text' name='user' value='$getuser' /></td>
		</tr>
		<tr>
			<td>Code:</td>
			<td><input type='text' name='user' value='$getcode' /></td>
		</tr>
		<tr>
			<td></td>
			<td><input type='submit' name='activatebtn' value='Activate' /></td>
		</tr>
		</table>
		</form>";
?>

</body>
</html>
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