Russia Posted June 30, 2013 Share Posted June 30, 2013 Hey guys I am trying to export a csv in my script and it works perfectly. Now what I need to do, is rename the columns to clean names and proper names before fully exporting the csv. Here is a picture of the database table: Here is the code: <?php include_once "config.php"; $table = 'patients'; // table you want to export $file = 'export'; // csv name. $result = mysql_query("SHOW COLUMNS FROM " . $table . ""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'] . ","; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM " . $table . ""); while ($rowr = mysql_fetch_row($values)) { for ($j = 0; $j < $i; $j++) { $csv_output .= $rowr[$j] . ", "; } $csv_output .= "\n"; } $filename = $file . "_" . date("d-m-Y_H-i", time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header("Content-disposition: filename=" . $filename . ".csv"); print $csv_output; exit; ?> As you can see it fetches the table names from this code: $result = mysql_query("SHOW COLUMNS FROM " . $table . ""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'] . ","; $i++; } } Now what I am trying to do is allow it to rename the database tables from pat_id to Patient ID pat_fname to Patient First Name pat_lname to Patient Last name and so on. To make it looks neat and readable in the csv file. How am I able to do that? I already tried a few codes like: $query = 'SHOW COLUMNS pat_id AS "user_id", pat_fname AS "first name", pat_lname AS "last name" FROM ' . $table;But it didnt work and gives off errors. Could someone with some knowledge help me out please. Quote Link to comment Share on other sites More sharing options...
litebearer Posted June 30, 2013 Share Posted June 30, 2013 http://php.about.com/od/learnmysql/qt/change_column_name.htm Quote Link to comment Share on other sites More sharing options...
Russia Posted June 30, 2013 Author Share Posted June 30, 2013 I managed to figure out that part: $result = mysql_query("SHOW COLUMNS FROM " . $table . ""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { //$csv_output .= $row['Field'] . ","; $csv_output = "IME Date, Location, patientLast, Firstname, IMEcompany, Show Y/N, Billed"; $i++; } } Now how do I rearange around the second part where it lists the rows, I would like the column Last Name to come before First Name and Location to come after IME Date. This is the part that gets the rows: $csv_output .= "\n"; $values = mysql_query("SELECT * FROM " . $table . ""); while ($rowr = mysql_fetch_row($values)) { for ($j = 0; $j < $i; $j++) { $csv_output .= $rowr[$j] . ", "; } $csv_output .= "\n"; } Can I change $rowr[$j] to instead look like $rowr['pat_name'] and list in order the way I want the rows to look like. Where would I put the Quote Link to comment Share on other sites More sharing options...
Russia Posted June 30, 2013 Author Share Posted June 30, 2013 (edited) I managed to fix that too by changing it into $values = mysql_query("SELECT pat_id,pat_lname,pat_fname,pat_date,pat_loc,pat_ins,pat_show FROM " . $table . ""); but one last thing I am stuck on is making it so it shows the name of the number in the offices table that is stored as a number in the patients table as pat_ins and pat_loc I did: $values = mysql_query("SELECT pat_id,pat_lname,pat_fname,pat_date,pat_loc,pat_ins,pat_show FROM patients INNER JOIN offices ON office_id = pat_loc INNER JOIN insurance ON ins_id = pat_ins "); Could someone show me the problem? Here is how the offices table looks like Edited June 30, 2013 by Russia Quote Link to comment Share on other sites More sharing options...
Barand Posted June 30, 2013 Share Posted June 30, 2013 (edited) my preferred method Code tags appear to be FUBAR so here it is without them $db = new mysqli(HOST, USERNAME, PASSWORD, DATABASE );$sql = "SELECT pat_id as `Patient ID` ,pat_lname as `Patient Last Name` ,pat_fname as `Patient First Name` ,pat_date as `Date` ,office_name as `Patient Location` ,pat_ins ,pat_show FROM patients INNER JOIN offices ON office_id = pat_loc INNER JOIN insurance ON ins_id = pat_ins ";sql2csv($db, $sql, 'mydata.csv', 1);//// function to download csv//function sql2csv($mysqli, $sql, $filename='', $headings=1){ if (!$filename) $f = 'download_' . date('ymdhi') . '.csv'; else $f = $filename; if ($fp) { $res = $mysqli->query($sql); if ($res) { header('Content-Type: text/csv'); header('Content-Disposition: attachment; filename="'.$f.'"'); header('Pragma: no-cache'); header('Expires: 0'); $row = $res->fetch_assoc(); if ($headings) { fputcsv($fp, array_keys($row)); } do { fputcsv($fp, $row); } while ($row = $res->fetch_assoc()); } else echo "Error in query"; fclose($fp); } } Edited June 30, 2013 by Barand Quote Link to comment Share on other sites More sharing options...
litebearer Posted June 30, 2013 Share Posted June 30, 2013 Its a new stealth feature Quote Link to comment Share on other sites More sharing options...
Russia Posted July 1, 2013 Author Share Posted July 1, 2013 Thanks for that code, but how do I join 2 tables to set a value of another table for a number of patients? Quote Link to comment Share on other sites More sharing options...
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