Add variable to an Object

[ttmt_101]

Hi all

 

This is following on from my previous questions.

 

I'm creating an <select> menu from an array and adding it to a variable

 

I'm also creating an Object.

 

How can I add the select menu variable to the Object.

 

This is all because I just need a named container to hold the select menu.

 

<?php


  class Color{

    var $select;

  }



  $col_Arr = array('Red','Green','Blue');



  $select_menu =  "<select>"; 


  for($i=0; $i<count($col_Arr); $i++){


    $select_menu .="<option>".$col_Arr[$i]."</option>";


  }


  echo "</select>";


  $My_Col = new Color;


  //How do I add $select_menu to $My_Col


  $My_Col->$select = $select_menu;


  $My_Col->$select_menu;



?>

[web_craftsman]

var $select;

Are you a fun of php4 ? Use public instead of var

 

Do this:

$My_Col->select = $select_menu;

[cpd]

A select menu isn't a colour and shouldn't be a property of a "Color" object. A "Select" could be an object of its own. 

 

@web_craftsman: You shouldn't really declare properties on the fly as you then open a can of encapsulation issue worms. 

Edited July 11, 2013 by cpd

[ttmt_101]

@web_craftsman: what encapsulation issues?

[ttmt_101]

@web_craftsman: I'm trying to create a named container I can reference later in the code to hold a select menu.

 

All this object will do is hold a reference to the select menu.

 

Is there another way of doing this?

Edited July 11, 2013 by ttmt_101

[web_craftsman]

your $select_menu variable is this named container.

[cpd]

Use a variable. Why are you using an object? There is absolutely no need for an object here and this is not object oriented programming in the slightest. You're just creating objects and giving them properties they shouldn't have and then assigning something to the property; that entire process is basically the same as assigning a normal variable.

[ttmt_101]

cpd - I know this isn't OOP in the slightest but I needed a named container, I thought i was going to include other things in it.

 

I think now i only need the select menu so it would work in a variable - I've made this so complicated for myself.

[web_craftsman]

I thought i was going to include other things in it.

For this you may use StdClass: Anonymous Objects

[cpd]

No you don't need to use the StdClass. A variable has a name: $username = "cpd";. Why is this not satisfactory? Given your description for the problem, there's no need to use an object at all.

 

@web_craftsman: from what you've suggested you don't seem to know what an object is for, when to use it, or how to use it. 

[web_craftsman]

@cpd: he wants "to include other things in it.". stdClass  object  is not a bad way to create some "advanced" variable if you don't want to use associative arrays.