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i have done coding for online exam..i want that when click on submit button than show the resul of corrrect and wrong answer..please help me soon..

ashish11

By ashish11
in PHP Coding Help

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ashish11 Newbie

ashish11

Posted
Posted (edited)

I have manage the database..

database name is online..

table name is question..

column name is serialno,question.optiona,optionb,optionc,optiond,answer..

now I want that when click on answer than should not save in database ..only by comparison to save answer result should be shown...

 

my code is this...

<html>
<head>
<style>
 ul{border:0; margin:0; padding:0;}

#pagination-digg li{
border:0; margin:0; padding:0;
font-size:11px;
list-style:none;
margin-right:2px;
}
#pagination-digg a{
border:solid 1px #9aafe5;
margin-right:2px;
}
#pagination-digg .previous-off,
#pagination-digg .next-off {
border:solid 1px #DEDEDE;
color:#888888;
display:block;
float:left;
font-weight:bold;
margin-right:2px;
padding:3px 4px;
}
#pagination-digg .next a,
#pagination-digg .previous a {
font-weight:bold;
}
#pagination-digg .active{
background:#2e6ab1;
color:#FFFFFF;
font-weight:bold;
display:block;
float:left;
padding:4px 6px;
}
#pagination-digg .non-active{
    background: #ff6633;
color: #ff6633;
font-weight:bold;
display:block;
float:left;
padding:4px 6px;
}
#pagination-digg .non-white{
    background: #FFFFFF;
color: #ff6633;
font-weight:bold;
display:block;
float:left;
padding:4px 6px;
}
#pagination-digg .non-purple{
    background: #800080;
color: #ff6633;
font-weight:bold;
display:block;
float:left;
padding:4px 6px;
}

#pagination-digg a:link,
#pagination-digg a:visited {
color:#0e509e;
display:block;
float:left;
padding:3px 6px;
text-decoration:none;
}
#pagination-digg a:hover{
border:solid 1px #0e509e
}

</style>
</head>
<body>
<?Php
include('connection.php');

error_reporting(0);

$id= $_GET['id'];

        
if(($id)){
$result = mysql_query("SELECT serialno,question,optiona,optionb,optionc,optiond FROM question where serialno=".$id."");
}
else{

$result = mysql_query("SELECT serialno,question,optiona,optionb,optionc,optiond FROM question where serialno=1");
}

while($result=mysql_fetch_array($result))
  {
 
  ?>
 

<form name='question' method="post" >
<?php echo $result['serialno'];?>.<?php echo $result['question'];
?>
<br/>

<input type="radio" name="a" value="<?php echo $result['optiona']; ?>"/><?php echo $result['optiona']; ?>
<br/>
<input type="radio" name="a" value="<?php
echo $result['optionb'];
?>" /><?php
echo $result['optionb'];
?>
<br/>
<input type="radio" name="a" value="<?php
echo $result['optionc'];
?>" /><?php
echo $result['optionc'];
?>
<br/>
<input type="radio" name="a" value="<?php
echo $result['optiond'];

?>" /><?php
echo $result['optiond'];

?>

 <?php  }

?>

<br />

<br /><br>
remind me later
<input type="checkbox" name="rememberMe" value="1" />
<input type="submit" name="next" style="width:50px;" value="Submit"/>
<input type="submit" name="next" style="width:50px;" value="Next"  onClick="window.location.href='online.php?id=<?php if (empty($id)){echo "2"; }else{echo $id+1;}?>';submit_form(); return false;" />
</form>
<?php if ($_SERVER['REQUEST_METHOD'] == 'POST') {
    $status= $_POST['a'];
   
    if(isset($_POST['rememberMe']))
    {
  $status =3;
 }
    elseif(!empty($status)){
        $status =1;
        //echo $status;
    }else{
       
        $status=2;
    }
   
    $query ="SELECT serialno FROM status WHERE serialno = '".$id."'";
$testResult = mysql_query($query) or die('Error, query failed');
   
if(mysql_fetch_array($testResult) == NULL){
  
    $sql = "INSERT INTO status ".
       "(serialno, status) ".
       "VALUES('$id','$status')";
    $result = mysql_query($sql) or die('Error, query failed');
}else{
    //update...
    $sql = "UPDATE status
        SET status='".$status."'
        WHERE serialno='".$id."'";
        $result = mysql_query($sql) or die('Error, query failed');       
}

   

if(! $result )
{
  die('Could not enter data: ' . mysql_error());
}
echo "Entered data successfully\n";

mysql_close($conn);
   $id=$id+1;
header("Location: ?id=$id");
}else {
  echo ""; 
   
};
?>

 

<ul id="pagination-digg">

    <?php $sql = mysql_query("SELECT * FROM status");
    while($res=mysql_fetch_array($sql)){
       
       $no = $res['serialno'];
         $status = $res['status'];
   
   
    ?>
   
<li <?php if($status == 1){ echo "class='active'" ;}else if($status == 2){ echo "class='non-active'";}else if($status == 3){ echo "class='non-purple'";}else { echo "class='non-white'";}?>><a href="?id=<?php echo "$no";?>"><?php echo $no;?></a></li>

    <?php } ?>

</ul>

</body>
</html>

online.php

Edited by ashish11
ashish11 Newbie

ashish11

Posted
  • Author
Posted

hello friend please help me in my code soon..i need urgent this code..if you have any query regarding code then post here I will tell you...

KevinM1 Advanced Member

KevinM1

Posted
Posted (edited)

1. The next time you post code here, please place it within 



 tags.  You can do it by simply clicking the <> button on our editor.


 


2. We don't complete other people's projects.  If you're having a specific problem, we'll help you figure out how to solve it, but we're not going to write it for you.  If you need that kind of service, make a post in our Freelancing section.


 


3. We don't really care if you think your problem is urgent.  That's not intended to be rude, it's just reality.  Everyone thinks their problem is urgent.


 


4. Repeatedly bumping your topic is against our ToS.  No one is guaranteed service here.  So, if no one answers your topic, the likely reason is because it's not a clear, concise question.



			
				


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