Call to a member function fetch_array()

[Davie33]

Hi am in need of abit of help from anyone,am having a problem with my latest topics file,I have an error that i can't seem to sort out.

 

Fatal error: Call to a member function fetch_array() on a non-object in C:\wamp\www\\templates\atest_topics.php on line 5

 

Here is my code thanks in advance.

<div class="nav_box"><div class="nav">Latest Topics</div>
<div class="nav_box2">
<?php
$query = yasDB_select("SELECT forumtopics.subjest,forumtopics.date,forumtopics.name,user.id,user.username,user.avatarfile.user.useavatar FROM forumtopics LEFT JOIN user ON forumtopic.name = user.username ORDER BY forumtopics.id DESC LIMIT 5");
while($row = $query->fetch_array(MYSQLI_ASSOC)){
      $id = $row['id'];
      $subject = $row['subject'];
      $date = date("m-j-y G:i");
      $username = $row['name'];
      if ($setting['seo'] == 'yes'){
      $topiclink = $setting['siteurl'].'forumtopics/'.$id.'/1.html';
      } else {
      $topiclink = $setting['siteurl'].'index.php?act=forumtopics&id='.$id;
      } if ($row['useavatar'] == '1') {
      $avatarimage = $setting['siteurl'].''.$row['avatarfile'];
      } else {
      $avatarimage = $setting['siteurl'].'useruploads/noavatar.JPG';
      } if ($setting['seo'] == 'yes') {
      $memberlink = $setting['siteurl'].'showmember/'.$id.'.html';
      } else {
      $memberlink = $setting['siteurl'].'index.php?act=showmember&id='.$id;
      }
?>
<a href="<?php echo $memberlink;?>"><img src="<?php echo $avatarimage;?>" width="40" height="40" align="center" title="<?php echo $username;?>"></a>
<a href="<?php echo $topiclink;?>"><?php echo $subject;?></a> - <?php echo $date;?><br>
<?php
}
$query->close();
?>
</div>
</div>

Edited August 22, 2013 by Davie33

[HippoZoned]

could there be a possible error in your query 

 

1. $query = yasDB_select("SELECT forumtopics.subjest,forumtopics.date,forumtopics.name,user.id,user.username,user.avatarfile.user.useavatar FROM forumtopics LEFT JOIN user ON forumtopic.name = user.username ORDER BY forumtopics.id DESC LIMIT 5");

 

the line i marked red and made bold the query looks off to me. I dont know if this was intentional but this seems like this is where the problem is. 

Edited August 22, 2013 by HippoZoned

[Davie33]

No i need that so the avatar's show and username is an url to the user profile.But for some reason it messes with forum topic links and username links

 

I see what you mean user.avatarfile.user.useavatar there is a dot between them when it should be a comma

 

But still didn't solve the problem.  user.avatarfile,user.useavatar

Edited August 22, 2013 by Davie33

[HippoZoned]

from what i see is you never got a result of your query. You just made the query but never asked for the result 

 

once you get the result you could write like 5 like this 

 

1. while($row = $result->fetch_array(MYSQLI_ASSOC)){

 

once that is done it should fix the problem but first you must get the result like so

 

$result = mysql_query($query);

 

or however you would need to grab the result of the query

Edited August 22, 2013 by HippoZoned

[Davie33]

I think this is what you mean ? but at the same time still the same error.

<div class="nav_box"><div class="nav">Latest Topics</div>
<div class="nav_box2">
<?php
$result = yasDB_select("SELECT * FROM forumtopics");
if ($result->num_rows == 0){
echo 'No Topics';
} else {
$query = yasDB_select("SELECT forumtopics.subjest,forumtopics.date,forumtopics.name,forumtopics.cat,user.id,user.username,user.avatarfile,user.useavatar FROM forumtopics LEFT JOIN user ON forumtopics.name = user.username ORDER BY forumtopics.id DESC LIMIT 5");
while($row = $query->fetch_array(MYSQLI_ASSOC)) {
      $id = $row['id'];
	  $subject = $row['subject'];
	  $date = date("m-j-y G:i");
	  $username = $row['name'];
	  if ($setting['seo'] == 'yes'){
	  $topiclink = $setting['siteurl'].'forumtopics/'.$id.'/1.html';
	  } else {
	  $topiclink = $setting['siteurl'].'index.php?act=forumtopics&id='.$id;
	  } if ($row['useavatar'] == '1') {
	  $avatarimage = $setting['siteurl'].'avatars/'.$row['avatarfile'];
	  } else {
	  $avatarimage = $setting['siteurl'].'avatars/useruploads/noavatar.JPG';
	  } if ($setting['seo'] == 'yes') {
	  $memberlink = $setting['siteurl'].'showmember/'.$id.'.html';
	  } else {
	  $memberlink = $setting['siteurl'].'index.php?act=showmember&id='.$id;
	  }
?>
<a href="<?php echo $memberlink;?>"><img src="<?php echo $avatarimage;?>" width="40" height="40" align="center" title="<?php echo $username;?>"></a>
<a href="<?php echo $topiclink;?>"><?php echo $subject;?></a> - <?php echo $date;?><br>
<?php }
}
$query->close();
?>
</div>
</div>

[trq]

You should check to see that $query is indeed what you expect it to be before you go ahead and use it like its an object.

 

$query seems a silly thing to name it too, its not a query.

[Davie33]

Sorry am abit tired need my sleep its just not working for me atm.

[Twysted]

try using a num_rows method in your sql and then using an if statement to check if the query was successful. if the if statement you can add the while loop.