host-provider Posted October 26, 2013 Share Posted October 26, 2013 Hello Sir, I need one help in my php file.. I have one database information in php file where form query go but when website lost database connection it shows error system is busy.. Is it Possible i add 2 database informations if one get lost query pass to another database if both lost then it show system is busy.. If you want i will show u my coding please reply.. Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/ Share on other sites More sharing options...
mentalist Posted October 26, 2013 Share Posted October 26, 2013 Yeah you can try as many connections as you like, just test that the connection variable isn't 0... Is your site really struggling so much that you're having this issue? (or is it a gameserver or such like?) Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455562 Share on other sites More sharing options...
host-provider Posted October 26, 2013 Author Share Posted October 26, 2013 Yeah you can try as many connections as you like, just test that the connection variable isn't 0... Is your site really struggling so much that you're having this issue? (or is it a gameserver or such like?) No it is just an sms site, i have local database and i have 2 networks on system both has static ip.. So if one network down it should connect from another ip thats why want to make database settings like this.. if you want to help please tell me can i send u code in pvt? Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455573 Share on other sites More sharing options...
mentalist Posted October 26, 2013 Share Posted October 26, 2013 No it is just an sms site, i have local database and i have 2 networks on system both has static ip.. So if one network down it should connect from another ip thats why want to make database settings like this.. if you want to help please tell me can i send u code in pvt? Post it here! Should be same as the standard code anyway, just tries again if fails...! Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455580 Share on other sites More sharing options...
host-provider Posted October 26, 2013 Author Share Posted October 26, 2013 Post it here! Should be same as the standard code anyway, just tries again if fails...! <?php $mytext = $_REQUEST['message']; if (strlen ($mytext) > 250) die("Unable to send your character limit is over 250"); $text_explode = explode(" ", $mytext); $count_explode = count($text_explode); $count_text = count($void_text); for ($i=0; $i<$count_text; $i++) { for ($j=0; $j<$count_explode; $j++) { if ($text_explode[$j]==$void_text[$i]) $words = "$words, $text_explode[$j]"; } } if (!empty($words)) { $error .= 'You have entered valgur or suspecious words'. $words.'\n'; } if (empty($_REQUEST['phone']) or strlen($_REQUEST['phone'])<11) { $error .= 'Enter Valid Phone Number e.g. 000000000000.<br><br><a href="index.php">Click here to go back, re-enter phone number!</a>'; } #if (empty($_REQUEST['name']) or strlen($_REQUEST['name'])<7) { #$error .= 'Please enter your name'; #} #if (empty($_REQUEST['message']) or strlen($_REQUEST['message'])<7) { #$error .= 'Please enter message'; #} @$db = mysql_connect("localhost", "username", "password"); if (!$db) { $error .= 'System Is Busy Please Wait Some Moment.'; } if (!empty($error)) { ?> <font color="#FF0000"><b><?php echo $error ?></b></font> <?php } else { mysql_select_db("database",$db); #$phone = $_POST['phone']; $phone = ltrim($_POST['phone'], 0); $name = $_POST['name']; $message = $_POST['message']; $phonenum = "+92$phone"; $message = ("From $name:\n$message\n[www.domain.com]"); $DirectionID = "2"; $TypeID = "1"; $StatusID = "1"; $StatusDetailsID = "200"; $ToAddress = "1"; $ChannelID = "0"; $BillingID = date("d/m/Y g:i a"); $FromAddress = $name; $CharsetID = "1"; $ToAddress = $phonenum; $Body = $message; $Subject = $_SERVER['REMOTE_ADDR']; error_reporting(0); session_start(); if(($_SESSION['security_code'] == $_POST['security_code']) && (!empty($_SESSION['security_code'])) ) { $query = "INSERT INTO Messages (DirectionID, TypeID, StatusDetailsID, StatusID, ChannelID, BillingID, FromAddress, Subject, CharsetID, ToAddress, Body) VALUES ('$DirectionID', '$TypeID', '$StatusDetailsID', '$StatusID', '$ChannelID', '$BillingID', '$FromAddress', '$Subject', '$CharsetID', '$ToAddress', '$Body')"; //echo "<b>Recipient Number: $phone<br> Sender Name: $name<br> Message: $message<br><br><br>"; echo "<b>Your SMS Sent Successfully To: 0$phone <br><br><a href='index.php'>Go Back To Send More Text SMS Now!</a></b>"; unset($_SESSION['security_code']); } else { echo "<b>Error: wrong security code</b><br><br>"; print "<a href='index.php'>Click here to go back, re-enter security code</a>"; } $result = mysql_query($query); { ?> <br> <br> Advertisement <?php } } error_reporting(0); mysql_close(); //// ?> look there i want to make connection of second database everything will be same just host name will be changed how to make it possible? Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455592 Share on other sites More sharing options...
mentalist Posted October 26, 2013 Share Posted October 26, 2013 @$db = mysql_connect("localhost", "username", "password"); if (!$db) { @$db = mysql_connect("remotehost", "username", "password"); if (!$db) { ...blah blah blah... } } Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455606 Share on other sites More sharing options...
host-provider Posted October 26, 2013 Author Share Posted October 26, 2013 @$db = mysql_connect("localhost", "username", "password"); if (!$db) { @$db = mysql_connect("remotehost", "username", "password"); if (!$db) { ...blah blah blah... } } you sure if both database are connected it will send from one first? Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455616 Share on other sites More sharing options...
mentalist Posted October 26, 2013 Share Posted October 26, 2013 you sure if both database are connected it will send from one first? The "if(!$db)" will obviously only execute if it's false! Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455624 Share on other sites More sharing options...
host-provider Posted October 27, 2013 Author Share Posted October 27, 2013 (edited) The "if(!$db)" will obviously only execute if it's false! Please tell me is it fine? @$db = mysql_connect("IP", "username", "password"); if (!$db) { @$db = mysql_connect("ip", "username", "password"); } if (!$db) { $error .= 'System Is Busy Please Wait Some Moment.'; } Edited October 27, 2013 by host-provider Quote Link to comment https://forums.phpfreaks.com/topic/283314-php-help/#findComment-1455643 Share on other sites More sharing options...
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