Problem with chained select

[stirrah]

Hey!

 

Im trying to do a chained select dropdown. 1 dropdown decides what should be shown in the second one...i think you all are familiar with this.

Anyway..im following this guide: http://www.yourinspirationweb.com/en/how-to-create-chained-select-with-php-and-jquery/

But something is wrong, i cant get it to work properly. 

 

My first dropdown is populating correct, but the second one is not working. If i choose something in the first dropdown, the second one just stops at "wait...". I think the problem is somewhere in add_project.php, but im not sure. Here is my code:

 

add_project.php:

<script type="text/javascript" src="http://code.jquery.com/jquery-1.10.1.min.js"></script>
        <script type="text/javascript">
            $(document).ready(function(){

$("select#category").change(function(){
    var id = $("select#category option:selected").attr('value');
    $.post("select_type.php", {id:id}, function(data){
        $("select#type").html(data);
        });
    });
 
            });
        </script>

<?php include "select.class.php"; ?>
 
    <form id="select_form">
        Choose a category:<br />
        <select id="category">
            <?php echo $opt->ShowCategory(); ?>
        </select>
            <br /><br />
 
           choose a type:<br />
            <select id="type">
                <option value="0">choose...</option>
            </select>
            <br /><br />
            <input type="submit" value="confirm" />
        </form>
        <div id="result"></div>

select.class.php:

<?php
class SelectList
{

      public function ShowCategory()
        {
            $sql = mysql_query("SELECT * FROM `projectCategory`");
          //  $res = mysql_query($sql,$this->conn);
            $category = '<option value="0">choose...</option>';
            while($row = mysql_fetch_array($sql))
            {
                $category .= '<option value="' . $row['categoryId'] . '">' . $row['categoryName'] . '</option>';
            }
            return $category;
        } 
 
        public function ShowType()
        {
            $query = mysql_query("SELECT huvudProjectId, huvudProjectName FROM `huvudProject` WHERE `categoryProject` = categoryId=$_POST[id]");
            $type = '<option value="0">choose...</option>';
            while($row = mysql_fetch_array($query))
            {
                $type .= '<option value="' . $row['huvudProjectId'] . '">' . $row['huvudProjectName'] . '</option>';
            }
            return $type;
        }
}
 
$opt = new SelectList();
?>

select_type.php:

<?php
include "select.class.php";
echo $opt->ShowType();
?>

Hope someone can help me with this! I've tried SO many hours but I cant find the problem.

[trq]

What have you done to debug the issue?

[stirrah]

I know that the query is OK, because i've run the method outside and it works. The second dropdown gets populated correctly. So the problem should be in the jquery-code i guess.

For me, it seems that the method never gets exececuted.

[trq]

So the problem should be in the jquery-code i guess.

So why would you post your question in the "PHP Applications" board? A board designed for questions relating to applications built with PHP?

[stirrah]

So why would you post your question in the "PHP Applications" board? A board designed for questions relating to applications built with PHP?

 

Oh...I'm so sorry, lol. Im so used to browse this forum...is it possible to move this thread or should a make another one?