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Make looping increment number

deib97

By deib97
in PHP Coding Help

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Ch0cu3r Newbie

Ch0cu3r

Posted
Posted

The sequence is simple. It is adding 1 to the previous number and then subtracting 7 if the new number is greater than 7, (resting the number sequence to 1 again)

<?php

// create emtpy array with 31 items set to zero
$seq = array_fill(0, 31, 0);

// set 1st, 15th and 26th postions with predifined number
$seq[0]  = 5; // 1st
$seq[14] = 1; // 15th
$seq[25] = 6; // 26th

// generate sequance
for($i = 1; $i < 31; $i++)
{
    // if current postion in sequance is greater than 0, skip it
    // these are our predefined numbers in the sequance
    if($seq[$i] > 0)
        continue;

    // work out next number in sequance
    // gets the previous number and adds 1
    $num = $seq[$i - 1] + 1;

    // if number is greater than 7, take 7 away
    if($num > 7)
        $num -= 7;

    // set the number
    $seq[$i] = $num;
}
?>
<style>
    th { color: red; width: 20px;}
    td { text-align: center; }
</style>
<table>
    <tr>
        <th><?php echo implode('</th><th>', range(1, 31)); ?></th>
    </tr>
    <tr>
        <td><?php echo implode('</td><td>', $seq); ?></td>
    </tr>
</table>
deib97 Member

deib97

Posted
  • Author
Posted

Expansion case for schedule shift.

https://dl.dropboxusercontent.com/s/2ksm9i7mrk91dd0/simulasi%20Roster.xls?dl=1&token_hash=AAGI7XXQjXJXSWQs7NQMbUTCBgOoCgn9xOKZnaYRbFYdsA

 

On this excel

  1. Hari ke u/ jadwal kerja is same solution from "Ch0cu3r", done
  2. This shift is determined by the pattern. example : 7/1 : 1 until 6x, 1 off ; if patern 14/1 : 1 until 6x, 2 until 7x and 1 Off.

Please help me bro..

Ch0cu3r Newbie

Ch0cu3r

Posted
Posted 



<?php


// array for lembur sequane

$seq['lembur'] = array();

$seq['lembur'][0]  = 3;


// array for kerja sequance

$seq['kerja']  = array();

$seq['kerja'][0]  = 1;


// array for shift sequance

$seq['shift']  = array();


// the max number foreach sequance

$seqances = array('lembur' => 7, 'kerja' => 14);


// generate the sequances

for($i = 0; $i < 31; $i++)

{

    // generate the number sequances for lembur and kerja

    foreach($seqances as $key => $maxSeq)

    {

        // if current postion is set, then skip it

        if(isset($seq[$key][$i]))

            continue;


        // get previous number in current squance

        $num = $seq[$key][$i - 1] + 1;


        // is number greater than the max sequance number

        // reset sequance

        if($num > $maxSeq)

            $num -= $maxSeq;


        // add number to current sequance

        $seq[$key][$i] = $num;

    }


    // the shift sequance

    if($seq['kerja'][$i] < 7)

        $shift = 1;

    elseif($seq['kerja'][$i] < 14)

        $shift = 2;

    else

        $shift = 'Off';


    $seq['shift'][$i]  = $shift;

}

?>

<style>

    th { color: red; width: 20px;}

    td { text-align: center; }

</style>

<table>

    <tr>

        <th>Tanggal</th>

        <th><?php echo implode('</th><th>', range(1, 31)); ?></th>

    </tr>

<?php foreach($seq as $key => $sequance): ?>

    <tr>

        <td><?php echo ucwords($key) ?></td>

        <td><?php echo implode('</td><td>', $sequance); ?></td>

    </tr>

<?php endforeach; ?>

</table>

 

deib97 Member

deib97

Posted
  • Author
Posted

Hi, Cho0cu3r

I have combination again. Im happy and try your code, but when I try to merge with my combination, the result not same with my simulation. How to change shift if pattern switch to 7/1 : 6x day 1 off  with dinamic shift 1 or 2.

inputan.jpg?dl=1&token_hash=AAFJsoZjMRyn

This my code :

<?php

// array for lembur sequane
$seq['lembur'] = array();
$seq['lembur'][0]  = 5;

// array for kerja sequance
$seq['kerja']  = array();
$seq['kerja'][0]  = 6;

$seq['kerja2']  = array();
$seq['kerja2'][0]  = 5;

// array for shift sequance
$seq['shift']  = array();
$seq['shift2']  = array();

// the max number foreach sequance
$seqances = array('lembur' => 7, 'kerja' => 14, 'kerja2' => 7);

// generate the sequances
for($i = 0; $i < 31; $i++)
{
    // generate the number sequances for lembur and kerja
    foreach($seqances as $key => $maxSeq)
    {
        // if current postion is set, then skip it
        if(isset($seq[$key][$i]))
            continue;

        // get previous number in current squance
        $num = $seq[$key][$i - 1] + 1;

        // is number greater than the max sequance number
        // reset sequance
        if($num > $maxSeq)
            $num -= $maxSeq;

        // add number to current sequance
        $seq[$key][$i] = $num;
    }

    // the shift sequance
    if($seq['kerja'][$i] < 7)
        $shift = 1;
    elseif($seq['kerja'][$i] < 14)
        $shift = 2;
    else
        $shift = 'Off';

	if($seq['kerja2'][$i] < 7)
        $shift2 = 2;  // change automatically 1 or 2 after off
    else
        $shift2 = 'Off';	
		
    $seq['shift'][$i]  = $shift;
	$seq['shift2'][$i]  = $shift2;
}
?>
<style>
    th { color: red; width: 20px;}
    td { text-align: center; }
</style>
<table>
    <tr>
        <th>Tanggal</th>
        <th><?php echo implode('</th><th>', range(1, 31)); ?></th>
    </tr>
<?php foreach($seq as $key => $sequance): ?>
    <tr>
        <td><?php echo ucwords($key) ?></td>
        <td><?php echo implode('</td><td>', $sequance); ?></td>
    </tr>
<?php endforeach; ?>
</table>

Based on your experience, Wheter such transactions should be stored in a database, with the target job to calculate the salary and overtime?

deib97 Member

deib97

Posted
  • Author
Posted

 

Add   $x = 0;   before the for loop

 

Now change the shift2 code to

    if($seq['shift2'][$i] < 7)
        $shift2 = ($x % 2 == 0) ? 2 : 1; // alternate between 2 and 1
    elseif($seq['shift2'][$i] == 7) {
        $shift2 = 'Off';
        $x++; // increment x for each 'Off'
    }

The result become 2 all.. where i put variable x?

before this? 

for($i = 0; $i < 31; $i++)
Ch0cu3r Newbie

Ch0cu3r

Posted
Posted

 

where i put variable x?

before this? 

for($i = 0; $i < 31; $i++)

Yes, the start of the for loop should read

$x = 0;
for($i = 0; $i < 31; $i++)

Edit. Ohh shoot. $seq['shift2'] should of been $seq['kerja2']

    if($seq['kerja2'][$i] < 7)
        $shift2 = ($x % 2 == 0) ? 2 : 1; // alternate between 2 and 1
    elseif($seq['kerja2'][$i] == 7) {
        $shift2 = 'Off';
        $x++; // increment x for each 'Off'
    }
Ch0cu3r Newbie

Ch0cu3r

Posted
Posted

Not quite understanding your question.

 

Are you wanting to make a dropdown and then chose which shift to display, eg if you select shift 1 you'd see

Shift	1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2

 If you select shift 2 then shift2 will be shown

Shift2	2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off

If you select both then shift 1 and 2 will be shown

Shift	1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2
Shift2  2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off
deib97 Member

deib97

Posted
  • Author
Posted

Hmm,,, please, you can try this bro..

this tes.php

<form action="shift.php" method="POST">
    Tanggal : <input type="text" name="tanggal" value="" /> <!--date value ex: 2014-01-01-->
    <br> 
    Hari ke : <select name="hari_ke"> 
        <!--this for Lembur, i was change to variable, thanks for support
        // array for lembur on line 4
        $seq['lembur'] = array();
        $seq['lembur'][0]  = 4, if selected 4 ;
        $seq['kerja2']  = array();
        $seq['kerja2'][0]  = 4, if selected 4 ;
        -->
        <option value="1">1</option>
        <option value="2">2</option>
        <option value="3">3</option>
        <option value="4">4</option>
        <option value="5">5</option>
        <option value="6">6</option>
        <option value="7">7</option>
    </select><br>
    Shift : <select name="shift"> 
        <option value="1">1</option> 
        <!--if this value selected, "shift mulai" must default to 1, patern pola shift 7/1
    1 1 1 Off 1 1 1 1 1	1 Off 1	1 1 1 1	1 Off 1	1 1 1 1	1 Off 1	1 1 1 1	1
        -->
        <option value="2">2</option>
        <!--if this value selected, "shift mulai" must default to 1, patern pola shift 7/1
    2 2 2 Off 2 2 2 2 2	2 Off 2	2 2 2 2	2 Off 2	2 2 2 2	2 Off 2	2 2 2 2	2
        -->
        <option value="3">1 dan 2</option>
        <!--if this value selected, "shift mulai", can be change to 1 or 2 in shift mulai
        -->
    </select> *if selected 1, must be default or automatically "shift mulai" is 1,<br> *if selected 2, must be default or automatically "shift mulai" is 2,<br> *if selected 1 and 2, must be can change "shift mulai" to 1 or 2
    <br>
    Shift mulai : <select name="shift_mulai"> 
        <option>1</option>
        <!--if this value selected, based on shift value 3 => 1 dan 2, shift start for 1 and continue to 2, patern pola shift 7/1
    1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1
        -->
        <option>2</option>
        <!--if this value selected, based on shift value 3 => 1 dan 2, shift start for 2 and continue to 1, patern pola shift 7/1
    2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2
        -->
    </select> <br>
    Pola : <select name="pola_shift">
        <option value="1">7/1</option>
        <option value="2">14/1</option>
    </select><br><input type="submit" value="submit" />
</form>

and shift.php

<?php
  $datei=$_POST["tanggal"];
  $day_number=$_POST["hari_ke"];
  $shift=$_POST["shift"];
  $shift_start=$_POST["shift_mulai"];
  $pattern_shift=$_POST["pola_shift"];
  
  if ($pattern_shift == 1) {
      $hpattern=7;
  }
  else
  {
      $hpattern=14;
  }
  date_default_timezone_set('UTC');  
  $hasil = explode("-", $datei); 
  $hasil[2]; // day
  $hasil[1]; // month
  $d1=$hasil[2];
  $m1=$hasil[1];
  $y1=$hasil[0];
  $num = cal_days_in_month(CAL_GREGORIAN, $m1, $y1);
  $d2 = $num;
 /* $m2 = $m1;
  $y2 = $y1;
  $start_date = array($y1,$m1,$d1);
  $implode1 = implode("-", $start_date);
   $end_date = array($y2,$m2,$d2);
  $implode2 = implode("-", $end_date);
  while(strtotime($implode1) <= strtotime($implode2))
  {
	echo "$implode1 - ? <br>";
	$implode1 = date ("Y-m-d", strtotime("+1 day", strtotime($implode1)));
  } */
  
// array for lembur sequane
$seq['lembur'] = array();
$seq['lembur'][0]  = $day_number;

// array for kerja sequance
 $seq['kerja']  = array();
$seq['kerja'][0]  = $day_number; 

//$seq['kerja2']  = array();
//$seq['kerja2'][0]  = 4;

// array for shift sequance
$seq['shift']  = array();
//$seq['shift2']  = array();

// the max number foreach sequance , 'kerja2' => 7
$seqances = array('lembur' => 7, 'kerja' => $hpattern);
$x=0;
// generate the sequances
for($i = 0; $i < $d2; $i++)
{
    // generate the number sequances for lembur and kerja
    foreach($seqances as $key => $maxSeq)
    {
        // if current postion is set, then skip it
        if(isset($seq[$key][$i]))
            continue;

        // get previous number in current squance
        $num = $seq[$key][$i - 1] + 1;

        // is number greater than the max sequance number
        // reset sequance
        if($num > $maxSeq)
            $num -= $maxSeq;

        // add number to current sequance
        $seq[$key][$i] = $num;
    }
    
    if ($hpattern== 7 ){
        if($seq['kerja'][$i] < 7)
        $shift = $shift_start;
    else
        $shift = 'Off';
        
    } else if ($hpattern=14) {
    // the shift sequance
    if($seq['kerja'][$i] < 7)
        $shift = $shift_start;
    elseif($seq['kerja'][$i] < 14)
        $shift = $shift_start;
    else
        $shift = 'Off';
    }
//	if($seq['kerja2'][$i] < 7)
//        $shift2 = ($x % 2 == 0) ? 2 : 1; // alternate between 2 and 1
//    elseif($seq['kerja2'][$i] == 7) {
//        $shift2 = 'Off';
//        $x++; // increment x for each 'Off'
//    }	
		
    $seq['shift'][$i]  = $shift;
//	$seq['shift2'][$i]  = $shift2;
}
?>
<style>
    th { color: red; width: 20px;}
    td { text-align: center; }
</style>
<table>
    <tr>
        <th>Tanggal</th>
        <th><?php echo implode('</th><th>', range(1, $d2)); ?></th>
    </tr>
<?php foreach($seq as $key => $sequance): ?>
    <tr>
        <td><?php echo ucwords($key) ?></td>
        <td><?php echo implode('</td><td>', $sequance); ?></td>
    </tr>
<?php endforeach; ?>
</table>

with your code,  :

$x=0 before looping

	if($seq['kerja2'][$i] < 7)
        $shift2 = ($x % 2 == 0) ? 2 : 1; // alternate between 2 and 1
    elseif($seq['kerja2'][$i] == 7) {
        $shift2 = 'Off';
        $x++; // increment x for each 'Off'
    }

The result  will be shown :

Shift2  2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off 1 1 1 1 1 1 Off 2 2 2 2 2 2 Off

And i want to change shift start to 1 and continue to 2; or shift start to 2 and continue to 1

Maybe with a bit of explanation may help you to help me.

thanks

im stuck :

deib97 Member

deib97

Posted
  • Author
Posted

Based on excel for pattern 14/1,

Shift	1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2 2 2 2 2 2 Off 1 1 1 1 1 1 2 2

How to choose shift_start 1 or 2?? 

I change and modify your code become to :

1 1 1 1 1	1  Off Off  Off	Off	Off	Off	Off	Off	2  2	2 2	2 2	Off	Off	Off	Off	Off	Off	Off	Off	1 1 1
Ch0cu3r Newbie

Ch0cu3r

Posted
Posted

Try

<?php

$datei         = $_POST["tanggal"];
$day_number    = $_POST["hari_ke"];
$shift_start   = $_POST["shift_mulai"];
$shift_1dan2   = isset($_POST["shiftAlt"]) ? true : false;
$pattern_shift = $_POST["pola_shift"];

if ($pattern_shift == 1) {
    $hpattern = 7;
} else {
    $hpattern = 14;
}

$shiftStart = array( 1,         // first shift value
                     2          // secound shift value
                    );

if($shift_start == 2)
    $shiftStart = array_reverse($shiftStart); // reverse the shift values

date_default_timezone_set('UTC');
$hasil = explode("-", $datei); 

$d1=$hasil[2]; // day
$m1=$hasil[1]; // month
$y1=$hasil[0];
$num = cal_days_in_month(CAL_GREGORIAN, $m1, $y1);
$d2 = $num;
  
// array for lembur sequane
$seq['lembur'] = array();
$seq['lembur'][0]  = $day_number;

// array for kerja sequance
$seq['kerja']  = array();
$seq['kerja'][0]  = $day_number; 

//$seq['kerja2']  = array();
//$seq['kerja2'][0]  = 4;

// array for shift sequance
$seq['shift']  = array();
//$seq['shift2']  = array();

// the max number foreach sequance , 'kerja2' => 7
$seqances = array('lembur' => 7, 'kerja' => $hpattern);
$x = 0;
// generate the sequances
for($i = 0; $i < $d2; $i++)
{
    // generate the number sequances for lembur and kerja
    foreach($seqances as $key => $maxSeq)
    {
        // if current postion is set, then skip it
        if(isset($seq[$key][$i]))
            continue;

        // get previous number in current squance
        $num = $seq[$key][$i - 1] + 1;

        // is number greater than the max sequance number
        // reset sequance
        if($num > $maxSeq)
            $num -= $maxSeq;

        // add number to current sequance
        $seq[$key][$i] = $num;
    }

    $kerjaValue = $seq['kerja'][$i];

    // default shift value to off
    $shiftValue = 'Off';
    
    // if shift not with 1 dan 2
    if(!$shift_1dan2)
    {
        // Shift pattern 14/1
        if($hpattern == 14 && $kerjaValue < 14)
            $shiftValue = $shiftStart[1];

        if($kerjaValue < 7)
            $shiftValue = $shiftStart[0];
    }
    // shift 1 dan 2
    elseif($shift_1dan2)
    {
        if($kerjaValue < $hpattern)
           $shiftValue = ($x % 2 == 0) ? $shiftStart[0] : $shiftStart[1]; // alternate between shift values, when x is dividable by 2

        if($shiftValue == 'Off') $x++; // increment x when shift is Off
    }
		
    $seq['shift'][$i]  = $shiftValue;
}
?>
<style>
    th { color: red; width: 20px;}
    td { text-align: center; }
</style>
<table>
    <tr>
        <th>Tanggal</th>
        <th><?php echo implode('</th><th>', range(1, $d2)); ?></th>
    </tr>
<?php foreach($seq as $key => $sequance): ?>
    <tr>
        <td><?php echo ucwords($key) ?></td>
        <td><?php echo implode('</td><td>', $sequance); ?></td>
    </tr>
<?php endforeach; ?>
</table>

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