Echo Issue in php/html

[JBuss1503]

Hi Community, 

 

I have a page on my website which includes a form and a submit button. If a user enters the correct 6 digit code (210392) it will take them to a another page (Google in this example). However I get an error when I run it. My code is below:

<?php
session_start();
include('connection.php');
?>

<div id="authorise">
<form action="admin.html" method="POST" name="authorisation"><br>
<!--Product Comment Box--><br>
<p>Please enter your 4<br> digit authorisation code:<br> <br><input type="text" name="code"/></p><br>
<input type="submit" value="Log In"/>
</form>

<?php
if ( ($authorise != 210392)
echo "https://www.google.co.uk";
?>

The error I get is: 

 

 

 

Parse error: syntax error, unexpected T_ECHO in /web/users/l1071039/bobbin/login.php on line 24

 

All help is greatly appreciated. Thanks in advance

[JBuss1503]

It appears I was missing a bracket in the line 23. However I now get this error

 

Notice: Undefined variable: authorisation in /web/users/l1071039/bobbin/login.php on line 21 https://www.google.co.uk

Edited March 18, 2014 by JBuss1503

[cyberRobot]

It means that your $authorise variable is undefined. Is that variable supposed to come from the form? If so, you'll want to look into using $_POST and isset().

[JBuss1503]

No. Can I change the 'if' code so that it knows to check the content of the form?

 

THanks

[cyberRobot]

It sounds like you're trying to use the value which was entered in the "code" input. If that's the case, you could use $_POST['code'].

if(isset($_POST['code']) && $_POST['code'] != 210392) {
     echo "https://www.google.co.uk";
}

Note: since $_POST['code'] will be undefined until the form is submitted, I used isset() to prevent the page from showing an undefined variable message.

[JBuss1503]

Thanks for your help so far. I have made some changes including what you gave me and my code now looks like this

 

<form action="admin.php" method="POST" name="authorisation"><br>
<!--Product Comment Box--><br>
<p>Please enter your 4<br> digit authorisation code:<br> <br><input type="text" name="code"/></p><br>
<input type="submit" value="Log In"/>
</form>

<?php
if(isset($_POST['code']) && $_POST['code'] != 210392) {
     echo "https://www.google.co.uk";
}
?>

When I run it, I type I can leave it blank and it will take me to admin.php instead of google. Do I need to remove any code and how do I get it so that if the incorrect code is inputted it wont load the page. I having only started html/php last week so I am very new to this and all help is appreciated