Jump to content

Help with update form


adamhull

Recommended Posts

Hello I have a update form and it shows all results but when I go through to my final page it will not update the database with the new info any help?

Test.php




<?php
include "includes/db_connect.php";

$sql="SELECT * FROM users";
$result=mysql_query($sql);
?>

<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>
<table width="400" border="1" cellspacing="0" cellpadding="3">
<tr>
<td colspan="4"><strong>List data from mysql </strong> </td>
</tr>

<tr>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Lastname</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Update</strong></td>
</tr>

<?php
while($rows=mysql_fetch_array($result)){
?>

<tr>
<td><? echo $rows['username']; ?></td>
<td><? echo $rows['userlevel']; ?></td>
<td><? echo $rows['email']; ?></td>

// link to update.php and send value of id 
<td align="center"><a href="test1.php?id=<? echo $rows['id']; ?>">update</a></td>
</tr>

<?php
}
?>

</table>
</td>
</tr>
</table>

<?php
mysql_close();
?>

 

Test1.php

 

 


<?php
include "includes/db_connect.php";

// get value of id that sent from address bar
$id=$_GET['id'];

// Retrieve data from database 
$sql="SELECT * FROM users WHERE id='$id'";
$result=mysql_query($sql);
$rows=mysql_fetch_array($result);
?>

<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="testdata.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td> </td>
<td colspan="3"><strong>Update data in mysql</strong> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
<td align="center"> </td>
</tr>
<tr>
<td align="center"> </td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Lastname</strong></td>
<td align="center"><strong>Email</strong></td>
</tr>
<tr>
<td> </td>
<td align="center">
<input name="username" type="text" id="username" value="<? echo $rows['username']; ?>">
</td>
<td align="center">
<input name="userlevel" type="text" id="userlevel" value="<? echo $rows['userlevel']; ?>" size="15">
</td>
<td>
<input name="email" type="text" id="email" value="<? echo $rows['email']; ?>" size="15">
</td>
</tr>
<tr>
<td> </td>
<td>
<input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>">
</td>
<td align="center">
<input type="submit" name="Submit" value="Submit">
</td>
<td> </td>
</tr>
</table>
</td>
</form>
</tr>
</table>

<?php
// close connection 
mysql_close();
?>
Test data.php

<?  
include "includes/db_connect.php";
// update data in mysql database 
$sql="UPDATE users SET username='$username', userlevel='$userlevel', email='$email' WHERE id='$id'";
$result=mysql_query($sql);

// if successfully updated. 
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='list_records.php'>View result</a>";
}

else {
echo "ERROR";
}

?>
Link to comment
Share on other sites

You're not using the user-submitted data in testdata.php. You use $username, $userlevel, $email, and $id in the query, but they're not set from $_POST - nor are they sanitized, which leaves you wide open to all kinds of injection. Also, the mysql functions have been deprecated and are scheduled to be removed soon - use mysqli or pdo.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.