SQL error due to NOW()

[aquatradehub]

Hi, I have this form which should write the details to the database and display the results afterwards, enabling the user to create a diary.

 

Here is the code

<?php 
include 'core/init.php';
protect_page();
include 'includes/overall/header.php'; 

    $user_id = $_POST['user_id'];
	$username = $_POST['username'];
	$diary_entry = $_POST['diary_entry'];

	mysql_query("INSERT INTO diary (user_id, username, diary_entry, datetime) VALUES({$_SESSION['user_id']}, {$_SESSION['username']}, '$diary_entry', NOW())");
    die(mysql_error());
	

?>

    <form action="" method="POST">
	<input type="hidden" name="user_id" value="<?php echo $user_data['user_id']; ?>"></li>
    <input type="hidden" name="username" value="<?php echo $user_data['username']; ?>"></li>
	<ul>
		<li>
			Diary Entry*:<br>
			<textarea name="diary_entry"></textarea>
		</li>
		<li><input type="submit" value="Submit"></li>
		</ul>
	</form>
 
<?php
	$result = mysql_query("SELECT * FROM diary WHERE username = $username");

while($row = mysql_fetch_array($result))
  {
  echo "<ul>";
  echo "<li>" . 'Entry by' . $row['username'] . "</li>";
  echo "<li>" . 'Date of Entry' . $row['entry_date'] . "</li>";
  echo "<li>" . 'Diary Entry' . $row['diary_entry'] . "</li>";
  echo "</ul>";
  }
  ?> 

<?php 

include 'includes/overall/footer.php'; ?>

But I get this error

 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' , NOW())' at line 1

 

I cant work out whats wrong Please help!

[Zane]

Make sure $diary_entry is free of any and all apostrophes and backslashes.

Edited April 21, 2014 by Zane

[aquatradehub]

Hi thanks for your reply.  

 

$diary_entry does not contain anything until the user submits the form. The only thing is the form is not displayed. The only thing showing on that page is nothing.

[mac_gyver]

the query error is probably because your $_SESSION['username'] value is a string and it isn't enclosed by single-quotes.

 

some tips -

 

1) you should build your sql query statement in a php variable so that you can echo it to see what it actually is.

 

2) your form processing code needs to test if the form was submitted so that it only runs when there's some form data to use.

 

3) you need to validate external data before using it.

 

4) you need to escape string data before putting it into a query statement or you need to use prepared queries.

 

5) the mysql_ database functions are depreciated and will be removed from php in the future. you should be learning either mysqli or PDO functions. see this link - http://us2.php.net/manual/en/mysqlinfo.api.choosing.php