APiro Posted April 30, 2014 Share Posted April 30, 2014 (edited) Hello! I am trying to query a table, and if any of a set of strings is found in a column to return that record SELECT *, 0 as section FROM injuryreport WHERE report='yes' AND FIND_IN_SET(injury,'$commaList') which ends up looking like: SELECT *, 0 as section FROM injuryreport WHERE report='yes' AND FIND_IN_SET(injury,'shoulder,upper arm, elbow,lower arm') I am getting returns if the column ONLY contains ONE of the words, but I also want to get returns if column injury contains any combination so long as one of them is there. For example: Head, Shoulder, Upper Arm, Elbow, Lower Arm, Wrist, Hand, Fingers, Ribs Head, Shoulder Upper Arm, Elbow Can this be done with FIND_IN_SET or should I be using something else?! Thank you in advance! Edited April 30, 2014 by APiro Quote Link to comment Share on other sites More sharing options...
APiro Posted April 30, 2014 Author Share Posted April 30, 2014 (edited) To provide more specific information on what is preceeding this which may be helpful. I am querying a table for a list of body areas from a table that looks like this: location | general head | head face | head shoulder | arm upper arm | arm elbow | arm lower arm | arm wrist | hand hand | hand fingers | hand ribs | body chest | body back | body hip | leg upper leg | leg knee | leg lower leg | leg ankle | foot foot | foot toes | foot other | other where the $general variable is passed from a previous selection of 1 of the 7 distinct entries from the above table, I am using: $query = "SELECT GROUP_CONCAT(location) FROM injurylocations WHERE general='$general'"; // execute SQL statement $list = mysql_db_query($db, $query, $conn); // check for errors if (!$list) { echo("ERROR: " . mysql_error() . "\n"); } // check for results $querycheck=mysql_num_rows($list); if ($querycheck < 1) { echo ("I CANT FIND A LIST OF INJURY LOCATION REFERENCES"); } else { while($row=mysql_fetch_array($list)) { $commaList = $row['GROUP_CONCAT(location)']; } In the original example I posted above $general would have been passed as 'arm' thus producing my arm related comma deliniated list. I can change the way Im querying here for the list and then modify the subsequent query using FIND_IN_SET , but I can't figure out a clean way to use LIKE and be able to get an OR statement Edited April 30, 2014 by APiro Quote Link to comment Share on other sites More sharing options...
Psycho Posted April 30, 2014 Share Posted April 30, 2014 You're doing this the wrong way. You don't need to run the two queries. You only need one. A good indicator that there's a problem is the user of GROUP_CONCAT(). You should never be dealing with comma separated lists to compare/search for values. $query = "SELECT injuryreport.*, 0 AS section FROM injuryreport JOIN injurylocations ON injuryreport.injury = injurylocations.location WHERE report='yes' AND injurylocations.general='$general'"; $result = mysql_db_query($db, $query, $conn); // check for errors if (!$result) { die("ERROR: " . mysql_error()); } // check for results if (!mysql_num_rows($result)) { echo "I CANT FIND A LIST OF INJURY LOCATION REFERENCES"; } else { //Do something with the results } Quote Link to comment Share on other sites More sharing options...
APiro Posted April 30, 2014 Author Share Posted April 30, 2014 Hi PsychoThanks for taking some time to look. Your query results in the same - it returns 20 records.There are actually 26 records if I manually search with:injury LIKE '%shoulder%' ORinjury LIKE '%upper arm%' ORinjury LIKE '%elbow%' ORinjury LIKE '%lower arm%'I was trying to keep the question as simple as possible, but with the addition of joins I have to admit that Im actually doing a UNION ALL with another table that has the exact same structure so if I were to manually write it out with LIKE: (SELECT *, 0 as section FROM injuryreport WHERE report='yes' AND injury LIKE '%shoulder%' OR injury LIKE '%upper arm%' OR injury LIKE '%elbow%' OR injury LIKE '%lower arm%') UNION ALL (SELECT *, 1 as section FROM playoffinjuryreport WHERE report='yes' AND injury LIKE '%shoulder%' OR injury LIKE '%upper arm%' OR injury LIKE '%elbow%' OR injury LIKE '%lower arm%') ORDER by date ASC, user ASC I actually just went the completely retarded route of $commaList = $row['GROUP_CONCAT(location)']; $newcommaList = str_replace(",", "%' OR injury LIKE '%", $commaList); and then using the query: $getreports = "(SELECT *, 0 as section FROM injuryreport WHERE report='yes' AND injury LIKE '%$newcommaList%') UNION ALL (SELECT *, 1 as section FROM playoffinjuryreport WHERE report='yes' AND injury LIKE '%$newcommaList%') ORDER by date ASC, user ASC"; which works but is insanely and stupidly backwards lol.... Quote Link to comment Share on other sites More sharing options...
jazzman1 Posted April 30, 2014 Share Posted April 30, 2014 Psycho's sql logic is correct for me, just add an IN sql operator. Try, $query = "SELECT injuryreport.*, 0 AS section FROM injuryreport JOIN injurylocations ON injuryreport.injury = injurylocations.location WHERE report='yes' AND injurylocations.general IN ('$general'"); // list of items Quote Link to comment Share on other sites More sharing options...
APiro Posted April 30, 2014 Author Share Posted April 30, 2014 Hi Jazzman It just doesnt pick up any records that have data in that colum that looks like: Head, Shoulder Upper Arm, Elbow Lower Arm, Wrist Here are the results using that suggestion And here is the results using LIKE which picks them all up Quote Link to comment Share on other sites More sharing options...
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