Change option value php

[jpopuk]

Hi, I am creating a php script with date of birth fields. I have it so when I add a DOB it does it like this:

$dob_day	= isset($_POST['dob_day']) && is_numeric($_POST['dob_day']) && $_POST['dob_day'] > 0 && $_POST['dob_day'] <= 31 ? $_POST['dob_day'] : '';
$dob_month	= isset($_POST['dob_month']) ? check_input($_POST['dob_month']) : '';
$dob_year	= isset($_POST['dob_year']) && is_numeric($_POST['dob_year']) ? $_POST['dob_year'] : '';
$dob		= $dob_day . '' . $dob_month . '' . $dob_year;

This works absolutely fine.

 

The issue I am having is when I go to edit the DOB in the edit page. It never seems to display all the content correctly. This is how the fields are setup in the edit template:

<select name="dob_day">
	<option value="">Day</option>
	<?php for ($i = 1; $i <= 31; $i++) { ?>
	<option value="<?php echo $i; ?>"<?php echo $dob[0] == $i ? ' selected="selected"' : ''; ?>><?php echo $i; ?></option>
	<?php } ?>
</select>
<select name="dob_month">
	<option value="">Month</option>
	<option value=" January "<?php echo $dob[1] == 1 ? ' selected="selected"' : ''; ?>>January</option>
	<option value=" February "<?php echo $dob[1] == 2 ? ' selected="selected"' : ''; ?>>February</option>
	<option value=" March "<?php echo $dob[1] == 3 ? ' selected="selected"' : ''; ?>>March</option>
	<option value=" April "<?php echo $dob[1] == 4 ? ' selected="selected"' : ''; ?>>April</option>
	<option value=" May "<?php echo $dob[1] == 5 ? ' selected="selected"' : ''; ?>>May</option>
	<option value=" June "<?php echo $dob[1] == 6 ? ' selected="selected"' : ''; ?>>June</option>
	<option value=" July "<?php echo $dob[1] == 7 ? ' selected="selected"' : ''; ?>>July</option>
	<option value=" August "<?php echo $dob[1] == 8 ? ' selected="selected"' : ''; ?>>August</option>
	<option value=" Septembe r"<?php echo $dob[1] == 9 ? ' selected="selected"' : ''; ?>>September</option>
	<option value=" October "<?php echo $dob[1] == 10 ? ' selected="selected"' : ''; ?>>October</option>
	<option value=" November "<?php echo $dob[1] == 11 ? ' selected="selected"' : ''; ?>>November</option>
	<option value=" December "<?php echo $dob[1] == 12 ? ' selected="selected"' : ''; ?>>December</option>
</select>
<select name="dob_year">
	<option value="">Year</option>
	<?php for ($i = gmdate('Y', time() + ($user_data['time_offset'] * 3600) + ($config['add_time'] * 3600)); $i >= gmdate('Y', time() + ($user_data['time_offset'] * 3600) + ($config['add_time'] * 3600)) - 25; $i--) { ?>
	<option value="<?php echo $i; ?>"<?php echo $dob[2] == $i ? ' selected="selected"' : ''; ?>><?php echo $i; ?></option>
	<?php } ?>
</select>

This only allows the Day to show fine. - Month and Year just show as Month and Year in their respective dropdowns rather than the actual Month or Year.

 

I know in Month I need to change the numerical 1 through to 12 to the name of the months, but I am unsure on how to do this without messing up the code.

 

As for the year I have no clue to that what so ever.

 

If anyone has any advice or help that would be absolutely brilliant.

 

Thanks in advance,

 

Paul

[xXREDXIIIXx]

This is from a register form I created a long time ago I hope it will help you 

<?php // BIRTHDAY

$ms = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
$d = 1; ?>

<select name="b_day">
  <option value="Day">Day</option>
    <?php while ( $d <= 31 ) {
    echo '<option value="'.$d.'"'.($_POST['b_day'] == $d ? ' selected="selected"':'').'>'.$d.'</option>';
    $d++;
    } ?>
</select>

<select name="b_month">
  <?php
  foreach($ms as $m){
    echo '<option value="'.$m.'"'.($_POST['b_month'] == $m ? ' selected="selected"':'').'>'.$m.'</option>';
    $m++;
   } ?>
</select>

<select name="b_year">
  <?php
  $end = date('Y'); // Current Year
  $start = ($end - 100); // Current Year - 100
  $y = $start; ?>
  <option value="Year">Year</option>
  <? while( $y <= $end){
    echo '<option value="'.$y.'"'.($_POST['b_year'] == $y ? ' selected="selected"':'').'>'.$y.'</option>';
    $y++;
  }?>
</select>

[jpopuk]

Thanks for the reply. - I have had a look at this and unfortunately this will not solve my solution.

 

The data is coming from one from database entry (dob).

 

So essentially the database cell  dob will say: 1 January 2014 - rather than 3 individual cells (dob_day, dob_month, dob_year).

[bsmither]

This seems to be concatenating three apparent strings to one string.

$dob = $dob_day . '' . $dob_month . '' . $dob_year;

 

Then you are using $dob[0], $dob[1], $dob[2] as an array.

[xXREDXIIIXx]

But this is a string when pulled from a database.

$dob		= $dob_day . '' . $dob_month . '' . $dob_year;

you would need to break it down, before showing it

 

literally your going to see for example: 2 MAY 1986

 

you would need to explode this

$section = explode(" ", $dob);
$day = $section[0]; // 2
$month = $section[1]; // May
$year = $section[2]; // 1986

example of this in your script would be

<option value=" January "<?php echo $section[1]; == Janurary ? ' selected="selected"' : ''; ?>>January</option> // This would be false
<option value=" May "<?php echo $section[1]; == May ? ' selected="selected"' : ''; ?>>May</option> // This would be True as the month was may

That being said I would still use my way

$ms = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
<select name="b_month">
  <?php
  foreach($ms as $m){
    echo '<option value="'.$m.'"'.($section[1] == $m ? ' selected="selected"':'').'>'.$m.'</option>';
   } ?>
</select>

[jpopuk]

Yes that is correct. - When I go to edit the post though which is the form in first post, I am not sure why it is not showing correct content.

 

The dob_day field shows the day, but the month and year is not showing correct content even though it has been posted to the database.

[jpopuk]

So you think it would be better to break it up to dob_day, dob_month, dob_year rather than having have it being pulled from one database entry (dob)?

[xXREDXIIIXx]

So you think it would be better to break it up to dob_day, dob_month, dob_year rather than having have it being pulled from one database entry (dob)?

 

That's really down to you. you can do that or the way I said before. I personally split it up in the database. 

[jpopuk]

I used your method in the end and works a charm! - Thank you for your help!