QUICK help with making a variable a link

[man5]

$link	=	?><a href="post?id=<?php echo $id; ?>&title=<?php echo $slug_title; ?>"><?php echo $title; ?></a><?php

Basically what I am trying to do is get a url link of a current page that I'll be sending in an email. I have all the $_GET variables I need to duplicate the current url.  For some reason it's giving me an error. 

 

Can you please fix what is shown above into something that'll work?

 

Thanks.

Edited July 16, 2014 by man5

[DavidAM]

It would help us to help you if you would tell us what the error message says.

 

I don't think that is valid code. You start a PHP assignment and drop out of PHP.

You are also echoing values, they are going to go to the output, NOT the variable assignment.

You should just concatenate the variables into a string; or, my personal preference:

 

$link = sprintf('<a href="post?id=%s&title=%s">%s</a>', $id, $slug_title, $title);

[PravinS]

You can use it like this also

<?php
     $link = '<a href="post?id='.$id.'&title='.$slug_title.'">'.$title.'</a>';
?>

[man5]

Perfect! That's exactly what I needed.

 

Thanks fellas.