Resource id #4 -- Help :(

[Henaro]

Hello!~

I have encountered an error and I am in need of help.  Here is there error:

[code]Resource id #4[/code]


Here is the code that is producing it:

[code]<?PHP
$view_post = fopen ('posts.txt', 'rb');
$view_post = str_replace(' [ascii] ', '<pre>', $view_post);
$view_post = str_replace(' [/ascii] ', '</pre>', $view_post);
printf("$view_post");
?>[/code]

I am not sure what Resource id #4 is.  I google'd it and found a lot of stuff about MySQL, but I am not using MySQL.  If anyone could tell me what is wrong with this please do.

Thanks,
Henaro

[fert]

[code]
$view_post = fopen ('posts.txt', 'rb');
$view_post=fread($view_post,filesize("posts.txt"));
$view_post = str_replace(' [ascii] ', '<pre>', $view_post);
$view_post = str_replace(' [/ascii] ', '</pre>', $view_post);
echo $view_post;
fclose($view_post);
[/code]

[Henaro]

Wow thanks for the speedy reply.  It works good now.  Thanks :D

[kenrbnsn]

You do not want to use the same variable for both the file pointer (the result of the fopen) and a text string. A much better solution would be:
[code]<?php
$fp = fopen ('posts.txt', 'rb');
$view_post=fread($fp,filesize("posts.txt"));
$view_post = str_replace(' [ascii] ', '<pre>', $view_post);
$view_post = str_replace(' [/ascii] ', '</pre>', $view_post);
echo $view_post;
fclose($fp);
?>[/code]

Ken