New to Php

[wata]

hi people im new to php programming and sorry if i have posted it in the wrong section. i need some help if anyone is willing to help please post back i would really appricate it. thank you

[Caesar]

Please be a little more specific. If you have question or need help with existing code...please post it here and let us know where you are having trouble. Thanks.

[wata]

oh yeh well the thing is i wanna assign to variables my name and a mark (between 1-25). And Convert this mark out of 25 to a percentage. If the percentage is 70% or more print out the statement, with my name on and sayin you are a first class student!”
but i donno how to start it off so could some start it off for us please not askin to do all of it jus start it off. thank you

[help_needed]

answer the question please someone...... :'(

[corbin]

I just read what wata posted about 10 times, and I still have no idea what you want...

Anyways for the percent thing you could do

if($percent*4 >= 70) {
echo "You are a first class student.";
}
else {
echo "You are not a first class student.";
}

[help_needed]

here is the actual question:

[quote]1. Assign to variables your name and a mark (between 1-25).  Convert this mark out of 25 to a percentage.  If the percentage is 70% or more print out the statement, “<your name>, you are a first class student!”  (replacing <your name> with the value stored in the variable)  [/quote]

[help_needed]

[quote author=corbin link=topic=117040.msg477375#msg477375 date=1165024649]
I just read what wata posted about 10 times, and I still have no idea what you want...

Anyways for the percent thing you could do

if($percent*4 >= 70) {
echo "You are a first class student.";
}
else {
echo "You are not a first class student.";
}
[/quote]

where did you get the 4 from?

[ataria]

where did you get the 4 from?

I know I didn't post ittt. but, I know the reasoning behind it.

100/25 = 4.

If you want 100% to the highest possible, you need to times the percent by 4.
Hence, a 17.5 would be 70%

get it?

[help_needed]

[quote author=ataria link=topic=117040.msg477539#msg477539 date=1165068702]

where did you get the 4 from?

I know I didn't post ittt. but, I know the reasoning behind it.

100/25 = 4.

If you want 100% to the highest possible, you need to times the percent by 4.
Hence, a 17.5 would be 70%

get it?

thanks BUT
can you answer this please?

[quote]1.  Assign to variables your name and a mark (between 1-25).  Convert this mark out of 25 to a percentage.  If the percentage is 70% or more print out the statement, “<your name>, you are a first class student!”  (replacing <your name> with the value stored in the variable) [/quote]

[/quote]

[ataria]

Corbin already did it.

if($percent*4 >= 70) {
echo " {$name}, You are a first class student.";
}
else {
echo "You are not a first class student.";
}

to do the other thingg. (giving them the mark)

<?php
$random = rand(1,25);
$insert = mysql_query("INSERT INTO `table_name`(`column name`) VALUES ('{$random}'));
?>

[help_needed]

thats what it came out with:

$name='XYZ,10'; if($percent*4 >= 70) { print "$name,You are a first class student."; } else { echo "You are not a first class student."; }

[wata]

ive got a problem on the forth line

<?php
$name = "Wata"
$percent = 4
if $percent*4 >= 70 {
echo " {$name}, You are a first class student.";
}
else {
echo "You are not a first class student.";
?>

[keeB]

[code]
<?php
$name = "Wata";
$random = rand(1,25);
if ($random*4 >= 70) {
    echo " {$name}, You are a first class student.";
} else {
    echo "You are not a first class student.";
}
?>
[/code]

There you go

[papaface]

should be:
[code]<?php
$name = "Wata"
$percent = 4
if ($percent*4 >= 70) {
echo " {$name}, You are a first class student.";
}
else {
echo "You are not a first class student.";
}
?>[/code]
You forgot the ()'s and the } on the last else statement.
EDIT: ^^ posted at the same time with a slightly different peice of code.