removal of brackets

kimjessen · January 22, 2015

Hi Yes I start a new thread, this is probably the correct one.

I have solved my problem almost. the result ends with the end of a parenthesis.

see picture

how do I get it deleted.

<?php
$dir    = './data/test111';
$ddArray1 = scandir($dir,1);
?>
<html>
<head>
<title>Select Drop Down List</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
	
		<select name="file">
		<?php
		FOREACH($ddArray1 AS $file){
		PRINT '<option value="'.$file.'">'.$file.'</option>';
		}
		?>
		</select>


	<input type="submit"/>
	

	
</form>
</body>
</html>

<?php


if ($_POST) {
	
	echo '<pre&gt';
	print_r($_POST);
	$test='</pre&gt>';
	echo $test;
}
?>

CroNiX · January 22, 2015

So it's showing up after you submit the form? Not sure if it's the forum doing it or your code converting the > to &gt, but try:

if ($_POST) {
  echo '<pre>';
  print_r($_POST);
  echo '</pre>';
}

kimjessen · January 22, 2015

the &gt are right not a err.

yes it did make a difference, not for the better.

but a difference is something.

the result is here!

Array
(
[file] => test111-2015-01-22.csv
)

now I can almost imagine where the end brackets come from.

but how do I get them removed?

Moreover, many thanks for the help.

Edited January 22, 2015 by kimjessen

CroNiX · January 22, 2015

That's because you're printing the whole array using print_r, which stands for "print array". If you want just the file, then do:

if ($_POST) {
 echo $_POST['file']; //only echos the 'file' index from the $_POST array
}

kimjessen · January 22, 2015

hi yes it seemed to me that I had tried it, but I was wrong,

now I tried it again and now it works, super thank you

kimjessen · January 22, 2015

Hello again!

It does not work as I expected. I would combine it with the graph, but I only get an error when I press the button.

I understand: who is in error description but can it be solved, or do I need to have the graph to run on a page by itself. ?

error message looks like this.

"

Explanation:
HTTP headers have already been sent back to the browser indicating the data as text before the library got a chance to send it's image HTTP header to this browser. This makes it impossible for the library to send back image data to the browser (since that would be interpretated as text by the browser and show up as junk text).

Most likely you have some text in your script before the call to Graph::Stroke(). If this texts gets sent back to the browser the browser will assume that all data is plain text. Look for any text, even spaces and newlines, that might have been sent back to the browser.

For example it is a common mistake to leave a blank line before the opening "<?php". "

<?php
$dir    = './data/test111';
$ddArray1 = scandir($dir,1);
?>
<html>
<head>
<title>Select Drop Down List</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
		<select name="file">
		<?php
		FOREACH($ddArray1 AS $file){
		PRINT '<option value="'.$file.'">'.$file.'</option>';
		}
		?>
		</select>
 	<input type="submit"/>
	</form>
</body>
</html>
 <?php
 if ($_POST) {
 $id=$_POST['file']; //only echos the 'file' index from the $_POST array
 //echo $id;
define("LOG_FILE", "./data/test111/".$id);
	require_once('jpgraph/src/jpgraph.php');
	require_once('jpgraph/src/jpgraph_line.php');
	$times = array();
	$values = array();	
	$file_lines = file(LOG_FILE, FILE_IGNORE_NEW_LINES|FILE_SKIP_EMPTY_LINES);
	foreach($file_lines as $line_num => $line_value) {
		$line_elements = explode(",", $line_value);
		$times[] = date($line_elements[0]);
		$values[] = $line_elements[1];
	}
	
	$graph = new Graph(800, 400);
	$graph->SetFrame(false);
	$graph->SetScale('intint');
	$graph->SetMarginColor('white');
	$graph->title->Set("Temp midt tank");
	
	$graph->xaxis->SetTickLabels($times);
	$graph->yaxis->scale->SetAutoMin(0);
	$graph->yaxis->title->Set("°C");
	
	$graph->ygrid->SetFill($aFlg=true, $aColor1='white', $aColor2='gray9');
	$lineplot = new LinePlot($values);
	$lineplot->SetColor('blue');
	
	$graph->Add($lineplot);
	$graph->Stroke();
	
}

 


?>

CroNiX · January 22, 2015

I'm sorry, I don't know anything about that graphing class you're using.

kimjessen · January 22, 2015

Ok else anyone who has an idea

Barand · January 22, 2015

No guarantees, but try putting the php portion of your code in a separate file (mygraph.php) and use GET instead of post.

In a separate php file put

$id = whatever;

echo "<img src='mygraph.php?file=$id' />";

Edited January 22, 2015 by Barand

kimjessen · January 22, 2015

hey it works that's what I do today.

I would like to have it on the same page.

I think that I have to use a different graph library. possibly some java.

Barand · January 22, 2015

No problem now we have established that works

<?php
$dir = './data/test111';
$ddArray1 = scandir($dir,1);
?>
<html>
<head>
<title>Select Drop Down List</title>
</head>
<body>
<form action="" method="get">
<select name="file">
<?php
FOREACH($ddArray1 AS $file){
PRINT '<option value="'.$file.'">'.$file.'</option>';
}
?>
</select>
<input type="submit"/>
</form>
</body>
</html>

<?php
    if (isset($_GET['file'])) {
        $id = $_GET['file'];
        echo "<img src='mygraph.php?file=$id' />" ;
    }
?>

kimjessen · January 22, 2015

that one i need some further explanation.

Barand · January 22, 2015

You said you wanted the chart on the same page

kimjessen · January 22, 2015

hi guys you are just amazing.

It works just as I had hoped for, again many thanks.

Now we need to work a little with design and things like that.

This forum is great, no question seems too stupid, and being helped, thank you.

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