swatisonee Posted November 27, 2005 Share Posted November 27, 2005 Hi, I need to pick up a number which can occur in any one of two tables. It works well upto the point when i have to output the data to the screen. That is my report file shows a parse error. I have tried variations of the foll. code and all appear wrong. Any guidance please ? $sql11 = SELECT * FROM Enq WHERE Enqid='$enq' UNION SELECT * FROM Visit WHERE Visitid='$enq'; $result11 = mysql_query($sql11) or die (mysql_error()); $myrow11 = mysql_fetch_array($result11); $company = $myrow11["Company"]; printf("<tr> <td><font face=\"Tahoma\" size=\"2\"> %s </td> </tr>", $customer); I have tried the foll. variations with single and double quotes and all throw up an error. $enq will appear either in the Table Enq or in the Table Visit. It will not appear in both. I checked the tables and the value is correctly appearing there so its a matter of outputting it to the screen. " SELECT * FROM Enq WHERE Enqid='$enq' UNION SELECT * FROM Visit WHERE Visitid='$enq' "; " SELECT * FROM Enq WHERE Enqid='$enq' "UNION "SELECT * FROM Visit WHERE Visitid='$enq' "; Thanks. Swati Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/ Share on other sites More sharing options...
sqlmc Posted November 27, 2005 Share Posted November 27, 2005 Is your table structure for Enq and Visit is the same? If not, the UNION with a SELECT * may cause problems. If you only need a particualr value, or even multiple values try using aliases that match and that should work. So it would go something like this. SELECT Attribute_A as NeededValue FROM Enq WHERE Enqid='$enq' UNION SELECT Attribute_B as NeededValue FROM Visit WHERE Visitid='$enq Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9892 Share on other sites More sharing options...
swatisonee Posted November 27, 2005 Author Share Posted November 27, 2005 The table structures are not the same. No luck chanfging the code. I get the foll. error Parse error: parse error, unexpected T_STRING in /home/virtual/site126/fst/var/www/html/report_visit.php on line 148 which is the 1st line of the foll. code : I tried backticks for the field names and the table names but that didnt work either. Any thing else i could try pl ? Or maybe another mysql function that is more appropriate ? $sql11 = SELECT Company as '$customer' FROM Enq WHERE Enqid='$enq' UNION SELECT Company as '$customer' FROM Visit WHERE Visitid='$enq'; $myrow11 = mysql_fetch_array($result11); $customer = $myrow11["Company"]; Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9894 Share on other sites More sharing options...
sqlmc Posted November 27, 2005 Share Posted November 27, 2005 It looks like your using a varialbe for an alias. Try this. $sql11 = "SELECT Company FROM Enq WHERE Enqid='$enq' UNION SELECT Company FROM Visit WHERE Visitid='$enq'"; $result11 = mysql_query($sql11) or die (mysql_error()); $myrow11 = mysql_fetch_array($result11); $company = $myrow11["Company"]; Also what is the datatype for Visitid and Enqid? You're using single quotes, but if the field is numeric then this may cause an error. If these fileds are INTEGER for example remove the single quotes from the WHERE clause. Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9896 Share on other sites More sharing options...
swatisonee Posted November 27, 2005 Author Share Posted November 27, 2005 Both the id fields are integers so i got rid of the single quotes but i now get this error: You have an error in your SQL syntax near 'UNION SELECT `Company` FROM `Visit` WHERE Visitid=' at line 2 I removed all the backticks and the error remains...any thing else i can try pl ? thanks Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9897 Share on other sites More sharing options...
sqlmc Posted November 27, 2005 Share Posted November 27, 2005 Can you paste the code. Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9898 Share on other sites More sharing options...
swatisonee Posted November 27, 2005 Author Share Posted November 27, 2005 Yes. Here it is: <? include("protection.php"); ?> <font face="Tahoma" size="2"> <? if (!$month || !$year) die("Mandatory information not entered. Please use back button of browser."); ?> <div align="left"> <font face="Tahoma" size="2"> <? print(date("l F d, Y")); ?> <p> <b>Monthly Travel Report</b><br><br> <b>Name : <?php $month = $HTTP_POST_VARS["month"]; $year = $HTTP_POST_VARS["year"]; $serial = 0; mysql_connect("localhost", $dbname, $dbpasswd ) or die ("Unable to connect to server."); mysql_select_db($database) or die ("Unable to select database."); $result = mysql_query("SELECT * FROM `users` WHERE staff='$staff' "); $myrow = mysql_fetch_array($result); $first_name = $myrow["firstname"]; $last_name = $myrow["lastname"]; echo "<font color=\"RED\">$first_name $last_name</font><br>Month : <font color=\"RED\">"; if ($month == 1) { $month_name = "January"; echo $month_name; } if ($month == 2) { $month_name = "February"; echo $month_name; } if ($month == 3) { $month_name = "March"; echo $month_name; } if ($month == 4) { $month_name = "April"; echo $month_name; } if ($month == 5) { $month_name = "May"; echo $month_name; } if ($month == 6) { $month_name = "June"; echo $month_name; } if ($month == 7) { $month_name = "July"; echo $month_name; } if ($month == 8) { $month_name = "August"; echo $month_name; } if ($month == 9) { $month_name = "September"; echo $month_name; } if ($month == 10) { $month_name = "October"; echo $month_name; } if ($month == 11) { $month_name = "November"; echo $month_name; } if ($month == 12) { $month_name = "December"; echo $month_name; } echo ", $year</font)"; ?> </b><p> <table border="1" style="border-collapse: collapse" bordercolor="#111111" width="100%"> <tr bgcolor="#C7F1FE"> <td><b><font face="Tahoma" size="2">Serial</b></td> <td><b><font face="Tahoma" size="2">Start<br>Date</b></td> <td><b><font face="Tahoma" size="2">End<br>Date</b></td> <td><b><font face="Tahoma" size="2">Company</b></td> <td><b><font face="Tahoma" size="2">From</b></td> <td><b><font face="Tahoma" size="2">To</b></td> </tr> <?php $serial = 0; mysql_connect("localhost", $dbname, $dbpasswd ) or die ("Unable to connect to server."); mysql_select_db($database) or die ("Unable to select database."); $result = mysql_query("SELECT * FROM `Travel` WHERE staff='$staff' && MONTH(`Ending`)=$month && YEAR(`Ending`)=$year ORDER BY `Ending` asc"); if ($myrow = mysql_fetch_array($result)) { do { $enq=$myrow["Enqid"]; $sql11 = "SELECT `Company` FROM `Enq` WHERE `Enqid`=$enq UNION SELECT `Company` FROM `Visit` WHERE `Visitid`=$enq"; $result11 = mysql_query($sql11) or die (mysql_error()); $myrow11 = mysql_fetch_array($result11); $company = $myrow11["Company"]; $serial+=1; printf("<tr> <td><font face=\"Tahoma\" size=\"2\"> %s </td> <td><font face=\"Tahoma\" size=\"2\"> %s </td> <td><font face=\"Tahoma\" size=\"2\"> %s </td> <td><font face=\"Tahoma\" size=\"2\"> %s </td> <td><font face=\"Tahoma\" size=\"2\"> %s </td> <td><font face=\"Tahoma\" size=\"2\"> %s </td> </tr>", $serial, calculatedate($myrow["Starting"]), calculatedate($myrow["Ending"]), $company, $myrow["From"], $myrow["To"] ); } else { echo "Sorry, no records were found!"; } ?> </table> </div> Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9899 Share on other sites More sharing options...
sqlmc Posted November 27, 2005 Share Posted November 27, 2005 What version of MySQL are you running? Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9900 Share on other sites More sharing options...
ryanlwh Posted November 27, 2005 Share Posted November 27, 2005 yeah, older versions of mysql do not support union. also try to put () around the select statements [!--sql--][div class=\'sqltop\']SQL[/div][div class=\'sqlmain\'][!--sql1--]([span style=\'color:blue;font-weight:bold\']SELECT[/span] ....) UNION ([span style=\'color:blue;font-weight:bold\']SELECT[/span] ....) [!--sql2--][/div][!--sql3--] Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9901 Share on other sites More sharing options...
swatisonee Posted November 28, 2005 Author Share Posted November 28, 2005 Ver. 3.23.58 of My Sql. Isnt this dependent on what the site host gives you ? I use mysql front 2.5 to see my db. Tried putting thr () brackets but that gives the same error.....anyother suggestions pl ? Thanks. Swati Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9909 Share on other sites More sharing options...
sqlmc Posted November 28, 2005 Share Posted November 28, 2005 I think UNION wasn't supported until version 4, I ran a similar query on a 3.23 system and a 4.1 system and the UNION worked on the 4.1 system and failed on the 3.23. You may have to separate the queries and then put them together after you gathered the appropriate info. Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9918 Share on other sites More sharing options...
ryanlwh Posted November 28, 2005 Share Posted November 28, 2005 sqlmc was right, UNION is not supported until mysql 4... Quote Link to comment https://forums.phpfreaks.com/topic/2943-select-union-error-i-hope-i-am-using-the-correct-function/#findComment-9920 Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.