ViperG Posted December 5, 2006 Share Posted December 5, 2006 [code]$sqld = "SELECT listingsdbelements_field_value FROM default_en_listingsdbelements WHERE listingsdb_id = $current_ID AND listingsdbelements_field_name LIKE 'price' ";$recordsetdave= $conn->Execute($sqld);[/code]So now how do I get the value of price? I need to put it in a variable.(BTW I only need this one variable, so if there is an easier way to do this plz tell me) Link to comment https://forums.phpfreaks.com/topic/29475-im-a-noob-and-need-some-help/ Share on other sites More sharing options...
ViperG Posted December 5, 2006 Author Share Posted December 5, 2006 looks like I figured it out. [code]$sqld = "SELECT listingsdbelements_field_value FROM default_en_listingsdbelements WHERE listingsdb_id = $current_ID AND listingsdbelements_field_name LIKE 'price' "; $recordsetdave= mysql_query($sqld) or die("Could not select items"); $davec=0; while($davidvar=mysql_fetch_array($recordsetdave)) { $davec=$davidvar[0]; };[/code]I was trying to do it like this though $davec=$davidvar[price];$davec=$davidvar['price'];but that wouldn't work and im not sure why. Link to comment https://forums.phpfreaks.com/topic/29475-im-a-noob-and-need-some-help/#findComment-135281 Share on other sites More sharing options...
fenway Posted December 6, 2006 Share Posted December 6, 2006 Because you're using fetch_array, not fetch_assoc... so you're not getting back a hash. Link to comment https://forums.phpfreaks.com/topic/29475-im-a-noob-and-need-some-help/#findComment-135967 Share on other sites More sharing options...
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