ViperG Posted December 5, 2006 Share Posted December 5, 2006 [code]$sqld = "SELECT listingsdbelements_field_value FROM default_en_listingsdbelements WHERE listingsdb_id = $current_ID AND listingsdbelements_field_name LIKE 'price' ";$recordsetdave= $conn->Execute($sqld);[/code]So now how do I get the value of price? I need to put it in a variable.(BTW I only need this one variable, so if there is an easier way to do this plz tell me) Quote Link to comment Share on other sites More sharing options...
ViperG Posted December 5, 2006 Author Share Posted December 5, 2006 looks like I figured it out. [code]$sqld = "SELECT listingsdbelements_field_value FROM default_en_listingsdbelements WHERE listingsdb_id = $current_ID AND listingsdbelements_field_name LIKE 'price' "; $recordsetdave= mysql_query($sqld) or die("Could not select items"); $davec=0; while($davidvar=mysql_fetch_array($recordsetdave)) { $davec=$davidvar[0]; };[/code]I was trying to do it like this though $davec=$davidvar[price];$davec=$davidvar['price'];but that wouldn't work and im not sure why. Quote Link to comment Share on other sites More sharing options...
fenway Posted December 6, 2006 Share Posted December 6, 2006 Because you're using fetch_array, not fetch_assoc... so you're not getting back a hash. Quote Link to comment Share on other sites More sharing options...
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