Lassie Posted March 16, 2015 Share Posted March 16, 2015 I am stuck trying to think of how I can use the results from my query to create php variables into a form that I can use, further in my php script or pass to a javascript to displat a map If I can pass the vars to javascript what is the best/safe way to do this. I am thinking of var postcode = "<?php echo $postcode; ?>"; var latitude = "<?php echo $latitude; ?>"; var longitude = "<?php echo $longitude; ?>"; This is the query and problem The results of the echo KT17 51.34 -0.24 KT18 51.31 -0.26 KT19 51.35 -0.26 -0.26global $wpdb; $wpdb->show_errors();//debug $result = mysql_query("SELECT postcode,latitude,longitude FROM uk_postcodes WHERE town = '$town'AND county='$county' ");// Get the postcode and lat and long while ( $row = mysql_fetch_assoc( $result ) ) { $postcode=$row['postcode']; $latitude=$row['latitude']; $longitude=$row['longitude']; echo $postcode .'<br/>'; echo $latitude .'<br/>'; echo $longitude .'<br/>'; } //put php variables into the form postcode, latitude, longitude ? //pass to javascript to draw map. var locations = [ ['KT17', 51.34, -0.24, 4], ['KT18', 51.31, -0.26, 5] ['KT19', 51.35, -0.26, 5] ]; This is the javascript <script type="text/javascript"> //need var for each var locations = [ ['KT17', 51.34, -0.24, 4], ['KT18', 51.31, -0.26, 5] ['KT19', 51.35, -0.26, 5] ]; var map = new google.maps.Map(document.getElementById('map'), { zoom: 10, center: new google.maps.LatLng(51.35, -0.26),//need var for latling as centre of map mapTypeId: google.maps.MapTypeId.ROADMAP }); var infowindow = new google.maps.InfoWindow(); var marker, i; for (i = 0; i < locations.length; i++) { marker = new google.maps.Marker({ position: new google.maps.LatLng(locations[i][1], locations[i][2]), map: map }); google.maps.event.addListener(marker, 'click', (function(marker, i) { return function() { infowindow.setContent(locations[i][0]); infowindow.open(map, marker); } })(marker, i)); } </script> Quote Link to comment Share on other sites More sharing options...
rwhite35 Posted March 16, 2015 Share Posted March 16, 2015 You can use JSON encoding to pass variables from PHP to Javascript. I prefer a JS Object as apposed to a variable. <script> var coordObj = new Object; coordObj.postcode = <?php echo htmlspecialchars(json_encode($postcode), ENT_NOQUOTES); ?>; coordObj.latitude = <?php echo htmlspecialchars(json_encode($latitude), ENT_NOQUOTES); ?>; coordObj.longitude = <?php echo htmlspecialchars(json_encode($longitude), ENT_NOQUOTES); ?>; </script> Then to access your JS object, included later one in the same page render (this is not asynchronous). <script> var postcode = coordObj.postcode; var latitude = coordObj.latitude; var longitude = coordObj.longitude; //now do the rest of your stuff </script> Quote Link to comment Share on other sites More sharing options...
maxxd Posted March 16, 2015 Share Posted March 16, 2015 If I'm understanding your question properly, in WordPress you'll want to take a look at the register_script(), localize_script(), and enqueue_script() functions fired from the wp_enqueue_scripts action hook. function enqueueStuff(){ wp_register_script('script_id',$this->getPluginDirectory()."/js/yourJSFile.js"); wp_localize_script('script_id','script_data',array( 'postCode'=>$this->getPostCode(), 'latitude'=>$this->getLatitude(), 'longitude'=>$this->getLongitude() )); wp_enqueue_script('script_id'); } add_action('wp_enqueue_scripts','enqueueStuff'); Of course, the pathing to your JavaScript file and the methods getting the post code, latitude, and longitude will be different for you - these are random stubs, but that's the basic idea of it. Quote Link to comment Share on other sites More sharing options...
Lassie Posted March 17, 2015 Author Share Posted March 17, 2015 Thanks Guys I will work these through Quote Link to comment Share on other sites More sharing options...
Lassie Posted March 17, 2015 Author Share Posted March 17, 2015 Before solving the javascript challenge I need to get my result into a useable format. Each row has three cols and I need each row with the three cols for example and with vars. $co-ordinate 1=['KT17', 51.34, -0.24, 4], $co-ordinate 2=['KT18', 51.31, -0.26, 5] $co-ordinate 3 =['KT19', 51.35, -0.26, 5] $co-ordinate 1=['$postcode1', $lat1, $long1, 4],etc $co-ordinate 2=['$postcode2', 51.31, -0.26, 5] $co-ordinate 3 =['KT19', 51.35, -0.26, 5] So my problem is how to get to that from this, Any help appreciated. $i=0; while($row = mysql_fetch_assoc($result)) { $postcode[$i] = $row['postcode']; $latitude[$i] = $row['latitude']; $longitude[$i]= $row['longitude']; $i++; echo $poatcode[$i] .'<br/>'; echo$latitude[$i] .'<br/>'; echo $longitude[$i] .'<br/>'; } Quote Link to comment Share on other sites More sharing options...
cypher86 Posted March 17, 2015 Share Posted March 17, 2015 $row is already in that format. anyway try this $i=0; while($row = mysql_fetch_assoc($result)) { $co-ordinate[$i]= ( "postcode" => $row['postcode'], "latitude" => $row['latitude'], "longitude" => $row['longitude'] ); $i++; } Quote Link to comment Share on other sites More sharing options...
maxxd Posted March 17, 2015 Share Posted March 17, 2015 Before solving the javascript challenge I need to get my result into a useable format. Each row has three cols and I need each row with the three cols for example and with vars. $co-ordinate 1=['KT17', 51.34, -0.24, 4], $co-ordinate 2=['KT18', 51.31, -0.26, 5] $co-ordinate 3 =['KT19', 51.35, -0.26, 5] $co-ordinate 1=['$postcode1', $lat1, $long1, 4],etc $co-ordinate 2=['$postcode2', 51.31, -0.26, 5] $co-ordinate 3 =['KT19', 51.35, -0.26, 5] So my problem is how to get to that from this, Any help appreciated. $i=0; while($row = mysql_fetch_assoc($result)) { $postcode[$i] = $row['postcode']; $latitude[$i] = $row['latitude']; $longitude[$i]= $row['longitude']; $i++; echo $poatcode[$i] .'<br/>'; echo$latitude[$i] .'<br/>'; echo $longitude[$i] .'<br/>'; } Are you having difficulties with php output for screen or php output for JavaScript? Quote Link to comment Share on other sites More sharing options...
Lassie Posted March 17, 2015 Author Share Posted March 17, 2015 Thanks for coming back. I think my problem is with php screen before I go to the javascript. Quote Link to comment Share on other sites More sharing options...
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