ItsMeKam59 Posted May 13, 2015 Share Posted May 13, 2015 (edited) Hello, I have a problem with my code : <?php //// BEGIN CONSTANTS //// // coordinates for the skin's face $face_x = 8; $face_y = 8; $face_width = 8; $face_height = 8; // coordinates for the skin's "mask", i.e. the layer that is overlaid // on top of the face $mask_x = 40; $mask_y = 8; $mask_width = 8; $mask_height = 8; // size of the output image $avatar_width = 96; $avatar_height = 96; // The default skin. All hail Steve! $default_skin_url = 'http://halcyon-pvp.fr/dl/img/char.png'; //// END CONSTANTS //// // Try to load the user's skin from the Amazon S3 storage if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } if (!$skin) { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } // Set up a blank image to write to $avatar = imagecreatetruecolor($avatar_width, $avatar_height); // Resize and overlay the face region, as defined by the constants above imagecopyresized($avatar, $skin, 0, 0, $face_x, $face_y, $avatar_width, $avatar_height, $face_width, $face_height); // Resize and overlay the mask region imagecopyresized($avatar, $skin, 0, 0, $mask_x, $mask_y, $avatar_width, $avatar_height, $mask_width, $mask_height); // Finally, return the processed image as a png header('Content-Type: image/png'); imagepng($avatar); imagedestroy($avatar); ?> Here's the problem : if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } if (!$skin) { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } The code works properly, but I want to add a new if, so i wrote this : if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else (!$skin) { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } But it doesn't work Could someone help me ?Thanks ! Edited May 13, 2015 by ItsMeKam59 Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/ Share on other sites More sharing options...
CroNiX Posted May 13, 2015 Share Posted May 13, 2015 if (isset($_GET['user'])) { } elseif (isset($_GET['user'])) { //since this is checking the exact same thing as the first IF(), this will never get triggered since it's in the elseif() which will only happen if the first IF() isn't true, which it is } Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511722 Share on other sites More sharing options...
cyberRobot Posted May 13, 2015 Share Posted May 13, 2015 Try changing this else (!$skin) { To this elseif (!$skin) { Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511723 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 (edited) if (isset($_GET['user'])) { } elseif (isset($_GET['user'])) { //since this is checking the exact same thing as the first IF(), this will never get triggered since it's in the elseif() which will only happen if the first IF() isn't true, which it is } That what I want to do, if the IF is false, it goes at the Elseif, and if the Elseif is false, it goes at the else Try changing this else (!$skin) { To this elseif (!$skin) { It didn't worked I want to check if the PNG is in the first link, if false, it checks on the second link, if it's a second time false, it sets a default image Edited May 13, 2015 by ItsMeKam59 Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511724 Share on other sites More sharing options...
Ofarchades Posted May 13, 2015 Share Posted May 13, 2015 It may be beneficial to identify what it's not doing that you'd like it to be doing? Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511726 Share on other sites More sharing options...
CroNiX Posted May 13, 2015 Share Posted May 13, 2015 (edited) But you have a logic problem and you're essentially saying this: if ($something == 'a') { echo 'found in the IF'; } else if ($something == 'a') { echo 'found in the elseif'; } If something does == 'a', what will be echoed? It will never reach the elseif if something == 'a'. Edited May 13, 2015 by CroNiX Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511727 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 But you have a logic problem and you're essentially saying this: if ($something == 'a') { echo 'found in the IF'; } else if ($something == 'a') { echo 'found in the elseif'; } If something does == 'a', what will be echoed? It will never reach the elseif if something == 'a'. You didn't understood I think, it want : -if the file exists on http://abc.com, it gets it -if the if is false, it gets the file on http://othersite.com -if the both sites don't have any file, it sets a default image It may be beneficial to identify what it's not doing that you'd like it to be doing? I will do this, wait Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511728 Share on other sites More sharing options...
cyberRobot Posted May 13, 2015 Share Posted May 13, 2015 I want to check if the PNG is in the first link, if false, it checks on the second link, if it's a second time false, it sets a default image If you always want the last part to take place when the first two parts fail, you'll want to use "else". <?php if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } ?> Note that you don't indicate a condition with else. Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511729 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 (edited) If you always want the last part to take place when the first two parts fail, you'll want to use "else". <?php if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } ?> Note that you don't indicate a condition with else. How could I indicate a condition so ? Because I tried this : if(isset($_GET['user'])) { $user = htmlspecialchars($_GET['user']); } if (file_exists("http://halcyon-pvp.fr/skins/$user.png")) { $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif(file_exists("http://skins.minecraft.net/MinecraftSkins/$user.png")) { $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else { $skin = imagecreatefrompng($default_skin_url); } It sets the default image directly, or the file exists Edited May 13, 2015 by ItsMeKam59 Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511730 Share on other sites More sharing options...
cyberRobot Posted May 13, 2015 Share Posted May 13, 2015 Just to clarify, are we still trying to get the following if/elseif/else structure working? if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } Or do you have different code now? Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511732 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 Just to clarify, are we still trying to get the following if/elseif/else structure working? if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); } elseif (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } else { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } Or do you have different code now? It's almost the same code, i just added (file_exists and added the $user above the if to store properly the code Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511733 Share on other sites More sharing options...
mac_gyver Posted May 13, 2015 Share Posted May 13, 2015 (edited) you actually need separate if() statements, for the if(!$skin)... tests. the value you are testing is dependent on the previous if() statement, not exclusive of it. an if/elseif/else string of test are exclusive of each other. Edited May 13, 2015 by mac_gyver Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511734 Share on other sites More sharing options...
Ofarchades Posted May 13, 2015 Share Posted May 13, 2015 I'm going to guess that what you're trying to do is something like... if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); if (!$skin) { $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } } if (!isset($skin) || !$skin) // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } ? (I feel like there's so much wrong with all of this code, but I'm just going to let it slide ) Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511735 Share on other sites More sharing options...
CroNiX Posted May 13, 2015 Share Posted May 13, 2015 (edited) $image = $default_skin_url; //used as default if (isset($_GET['user'])) { //is the user set? $user = $_GET['user']; //Does the user image exist on site A? $site_a = "http://halcyon-pvp.fr/skins/$user.png"; $site_b = "http://skins.minecraft.net/MinecraftSkins/$user.png"; if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; } $skin = imagecreatefrompng($image); 1) If image exists on site_a, it uses that. 2) If image does not exist on site_a, it checks site_b. If it exists there, it uses that. 3) If image does not exist on site_a or site_b, it uses the default. Edited May 13, 2015 by CroNiX Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511736 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 I'm going to guess that what you're trying to do is something like... if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); if (!$skin) { $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } } if (!isset($skin) || !$skin) // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } ? (I feel like there's so much wrong with all of this code, but I'm just going to let it slide ) I fixed the errors, but this code don't work, there are many errors with the imagecopyresized (bottom of the code) $image = $default_skin_url; //used as default if (isset($_GET['user'])) { //is the user set? $user = $_GET['user']; //Does the user image exist on site A? $site_a = "http://halcyon-pvp.fr/skins/$user.png"; $site_b = "http://skins.minecraft.net/MinecraftSkins/$user.png"; if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; } $skin = imagecreatefrompng($image); 1) If image exists on site_a, it uses that. 2) If image does not exist on site_a, it checks site_b. If it exists there, it uses that. 3) If image does not exist on site_a or site_b, it uses the default. This code just work for the site_a, but when It should checks the site_b and the default, it says me : Warning: file_get_contents(http://halcyon-pvp.fr/skins/Blabla.png): failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in /home/halcyonp/public_html/skinHead.php on line 31 Warning: Cannot modify header information - headers already sent by (output started at /home/halcyonp/public_html/skinHead.php:31) in /home/halcyonp/public_html/skinHead.php on line 77 ‰PNG IHDR``múàoÏIDATxœíÜ1JAFáÉîHŒ&õb!6±ðÚÚ ^@ˆ……Bì¯ ØÚÚ‰x‹ØY¦PlD!wõoÀ ßWÿ¸ËsšÁ˜ÚùÑN ƒá'n^>†¸©Ê 7£q‰›rÌïó•ð¬µ•%Üd¸øçbk®Ž£Ç·wÜdY>‰÷ ³ ›Qàwïk·ý'Üx‚€€€€€€€€€€@ì?¿â(ßü“j O›Âûš'Ä<ðgùBÎS>8÷5O0000000000ˆ1%Qõw÷µƒí ~Ôê.nš&nö;ë¸ñ˜åüw¨øû4RîkÝÎfÊ;¡…oîîpÓ^nãÆb}&âˆÿ«*„³Ó+ÜìmMæ.¶8Ͽע(psqØÁ'Äf£•0à¢wyüû·IÔ»ægU7'¸Iù®~O0000000000øMÀEÿ+G4¯IEND®B`‚ It doesn't go on the others links, it stays on the site_a Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511737 Share on other sites More sharing options...
Ofarchades Posted May 13, 2015 Share Posted May 13, 2015 (edited) I fixed the errors, but this code don't work, there are many errors with the imagecopyresized (bottom of the code) What do you mean by this? With the other code, the warning is being thrown by the first file_get_contents not finding the file. Try adding @ before the function calls, I guess. Edited May 13, 2015 by Ofarchades Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511739 Share on other sites More sharing options...
cyberRobot Posted May 13, 2015 Share Posted May 13, 2015 Instead of using file_get_contents() here: if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; You could try using file_exists(), like you did before. Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511740 Share on other sites More sharing options...
Ofarchades Posted May 13, 2015 Share Posted May 13, 2015 Instead of using file_get_contents() here: if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; You could try using file_exists(), like you did before. Ideally once we've established what he's trying to achieve, we'd want to get him to change it so that the image doesn't need to be downloaded twice (once for the file_get_contents/whatever and then again for the imagecreatefrompng) i.e. store the result in a variable and pass it to imagecreatefromstring. At this stage, I fear that may just cause more confusion than there is already. Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511741 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 Instead of using file_get_contents() here: if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; You could try using file_exists(), like you did before. If i do this, it directly goes on the default image What do you mean by this? With the other code, the warning is being thrown by the first file_get_contents not finding the file. Try adding @ before the function calls, I guess. It didn't worked Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511757 Share on other sites More sharing options...
Ofarchades Posted May 13, 2015 Share Posted May 13, 2015 Would you be able to post all the code you currently have? I can't see any reason why the code we've posted here wouldn't work; there has to be something else going on. Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511758 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 (edited) Here's the FULL code (I have cancelled all the wrong things since Cronix's answer) : <?php //// BEGIN CONSTANTS //// // coordinates for the skin's face $face_x = 8; $face_y = 8; $face_width = 8; $face_height = 8; // coordinates for the skin's "mask", i.e. the layer that is overlaid // on top of the face $mask_x = 40; $mask_y = 8; $mask_width = 8; $mask_height = 8; // size of the output image $avatar_width = 96; $avatar_height = 96; // The default skin. All hail Steve! $default_skin_url = 'http://halcyon-pvp.fr/dl/img/char.png'; //// END CONSTANTS //// $image = $default_skin_url; //used as default if (isset($_GET['user'])) { //is the user set? $user = $_GET['user']; //Does the user image exist on site A? $site_a = "http://halcyon-pvp.fr/skins/$user.png"; $site_b = "http://skins.minecraft.net/MinecraftSkins/$user.png"; if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; } $skin = imagecreatefrompng($image); // Set up a blank image to write to $avatar = imagecreatetruecolor($avatar_width, $avatar_height); // Resize and overlay the face region, as defined by the constants above imagecopyresized($avatar, $skin, 0, 0, $face_x, $face_y, $avatar_width, $avatar_height, $face_width, $face_height); // Resize and overlay the mask region imagecopyresized($avatar, $skin, 0, 0, $mask_x, $mask_y, $avatar_width, $avatar_height, $mask_width, $mask_height); // Finally, return the processed image as a png header('Content-Type: image/png'); imagepng($avatar); imagedestroy($avatar); ?> It maybe comes cause of the Resize or the Header ?You could try the code, drop this code on a file like skin.php, drag in on your FTP, and try "http://yoursite.com/skin.php?user=AxploOdee"It's the site_a, the Head will AppearsTo try the site_b write "http://yoursite.com/skin.php?user=Ewearys"To try the defaut, write the name of your choice. The AxploOdee image exists on the site_a, and Ewearys on the site_b Edited May 13, 2015 by ItsMeKam59 Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511759 Share on other sites More sharing options...
Solution Ofarchades Posted May 13, 2015 Solution Share Posted May 13, 2015 (edited) I just tested it. Like I said, change if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; to if (@file_get_contents($site_a) !== FALSE) $image = $site_a; else if (@file_get_contents($site_b) !== FALSE) $image = $site_b; and it works. Also the code I posted earlier would have worked, but it was missing an opening brace that I wasn't able to see because I wrote it in this site's edit box. You should have easily seen it in your code editor, though. You are using a code editor... aren't you? Anyway, as mentioned before, you don't really want to call both file_get_contents and imagecreatefrompng because that means the image will be downloaded twice from the remote server. Instead, try: <?php //// BEGIN CONSTANTS //// // coordinates for the skin's face $face_x = 8; $face_y = 8; $face_width = 8; $face_height = 8; // coordinates for the skin's "mask", i.e. the layer that is overlaid // on top of the face $mask_x = 40; $mask_y = 8; $mask_width = 8; $mask_height = 8; // size of the output image $avatar_width = 96; $avatar_height = 96; // The default skin. All hail Steve! $default_skin_url = 'http://halcyon-pvp.fr/dl/img/char.png'; //// END CONSTANTS //// if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); if (!$skin) { $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } } if (!isset($skin) || !$skin) { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } // Set up a blank image to write to $avatar = imagecreatetruecolor($avatar_width, $avatar_height); // Resize and overlay the face region, as defined by the constants above imagecopyresized($avatar, $skin, 0, 0, $face_x, $face_y, $avatar_width, $avatar_height, $face_width, $face_height); // Resize and overlay the mask region imagecopyresized($avatar, $skin, 0, 0, $mask_x, $mask_y, $avatar_width, $avatar_height, $mask_width, $mask_height); // Finally, return the processed image as a png header('Content-Type: image/png'); imagepng($avatar); imagedestroy($avatar); ?> Alternatively, you could keep the existing file_get_contents code, but save the result to a variable and pass it to imagecreatefromstring. The only problem with that is that imagecreatefromstring uses more memory. Edited May 13, 2015 by Ofarchades Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511764 Share on other sites More sharing options...
ItsMeKam59 Posted May 13, 2015 Author Share Posted May 13, 2015 I just tested it. Like I said, change if (file_get_contents($site_a) !== FALSE) $image = $site_a; else if (file_get_contents($site_b) !== FALSE) $image = $site_b; to if (@file_get_contents($site_a) !== FALSE) $image = $site_a; else if (@file_get_contents($site_b) !== FALSE) $image = $site_b; and it works. Also the code I posted earlier would have worked, but it was missing an opening brace that I wasn't able to see because I wrote it in this site's edit box. You should have easily seen it in your code editor, though. You are using a code editor... aren't you? Anyway, as mentioned before, you don't really want to call both file_get_contents and imagecreatefrompng because that means the image will be downloaded twice from the remote server. Instead, try: <?php //// BEGIN CONSTANTS //// // coordinates for the skin's face $face_x = 8; $face_y = 8; $face_width = 8; $face_height = 8; // coordinates for the skin's "mask", i.e. the layer that is overlaid // on top of the face $mask_x = 40; $mask_y = 8; $mask_width = 8; $mask_height = 8; // size of the output image $avatar_width = 96; $avatar_height = 96; // The default skin. All hail Steve! $default_skin_url = 'http://halcyon-pvp.fr/dl/img/char.png'; //// END CONSTANTS //// if (isset($_GET['user'])) { $user = $_GET['user']; $skin = @imagecreatefrompng("http://halcyon-pvp.fr/skins/$user.png"); if (!$skin) { $skin = @imagecreatefrompng("http://skins.minecraft.net/MinecraftSkins/$user.png"); } } if (!isset($skin) || !$skin) { // If skin could not be retrieved, display Steve $skin = imagecreatefrompng($default_skin_url); } // Set up a blank image to write to $avatar = imagecreatetruecolor($avatar_width, $avatar_height); // Resize and overlay the face region, as defined by the constants above imagecopyresized($avatar, $skin, 0, 0, $face_x, $face_y, $avatar_width, $avatar_height, $face_width, $face_height); // Resize and overlay the mask region imagecopyresized($avatar, $skin, 0, 0, $mask_x, $mask_y, $avatar_width, $avatar_height, $mask_width, $mask_height); // Finally, return the processed image as a png header('Content-Type: image/png'); imagepng($avatar); imagedestroy($avatar); ?> Alternatively, you could keep the existing file_get_contents code, but save the result to a variable and pass it to imagecreatefromstring. The only problem with that is that imagecreatefromstring uses more memory. Oh yes, it works! I think I mistook something, thanks ! Quote Link to comment https://forums.phpfreaks.com/topic/296291-more-than-one-if-dont-work/#findComment-1511765 Share on other sites More sharing options...
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