php/html help

[black_pearl]

hey guys i am pretty new to html and php and i have a little problem

 

here is the code : 

 

<div id="gallery" align="center">

    <div class="thumbnails">

        <?php

            for ($i = 1; $i <= $total_photos; $i++){ ?>

                <img onmouseover="preview.src=<?php echo $car[0]->photo . $i . '()';?>.src"  src="<?php echo $car[0]->photo1()?>" alt=""/>

       <?php } ?>

 

</div><br/>

 

--------------------------------------------------------------------

 

when i do  : <img onmouseover="preview.src=<?php echo $car[0]->photo1()?>.src"  src="<?php echo $car[0]->photo1()?>" alt=""/>

it works fine gives me the photo1 from the database but i want to get all the other photos as i tried on the code above and i have tried so many things but cant come up with the right prob missing something a rule or something like that

 

if anyone can help out please

thanks

 

[cyberRobot]

Is it perhaps that this

<img onmouseover="preview.src=<?php echo $car[0]->photo . $i . '()';?>.src"  src="<?php echo $car[0]->photo1()?>" alt=""/>

Needs to be changed to this

<img onmouseover="preview.src=<?php echo $car[0]->photo . $i . '()';?>.src"  src="<?php echo $car[0]->photo . $i . '()'; ?>" alt=""/>

[black_pearl]

hey cyberRobot tyvrm for replying

 

yes i have already tried this one out and it gives me this error : http://prntscr.com/7vas9m

 

when i do $car->photo . $1 . '()'   i dont know why it just take $car->photo and thats why i get error coz there is nothing called like photo on the db or anywhere else and it also says it in the error  : undefined Car::$photo

Edited July 21, 2015 by black_pearl

[cyberRobot]

If that doesn't work...which it probably won't, where does $car come from. Are you able to show the code where photo1() is defined? I imagine that it comes from a class definition. If that's correct, does the class have multiple methods like photo1(), photo2(), etc.?

[black_pearl]

yes this is it and i am trying to do $car[0]->photo1(), $car[0]->photo2() , $car[0]->photo3() ,$car[0]->photo4() ..

[cyberRobot]

It looks like you can use the call_user_func() function to dynamically name your class methods. You could try something like the following:

<img onmouseover="preview.src=<?php echo call_user_func(array($car[0], "photo$i")); ?>.src"  src="<?php echo call_user_func(array($car[0], "photo$i")); ?>" alt=""/>

[black_pearl]

just tried it gives me empty items,

i just copied the code u posted did i have to change something else anywhere ?

[black_pearl]

if u dont mind we can do a teamviewer session ? would be easier ah shi i dont have a mic 

[cyberRobot]

Hmm...the code seems to work for me when I try the following:

<?php
class testClass {
    public function photo1() {
        print '<div>In photo1</div>';
    }
 
    public function photo2() {
        print '<div>In photo2</div>';
    }
 
    public function photo3() {
        print '<div>In photo3</div>';
    }
}
 
$car = array();
$car[] = new testClass;
$total_photos = 3;
 
for ($i = 1; $i <= $total_photos; $i++) {
    echo call_user_func(array($car[0], "photo$i"));
}
?>

 

 

Do you know which version of PHP you're using? Is PHP set to show all errors and warnings? Note that you can add the following to the top of your script during the debugging process:

error_reporting(E_ALL);
ini_set('display_errors', 1);

 

 

[Ch0cu3r]

@black_pearl Why does your class have functions photo1(), photo2(), photo3() etc defined? Why not just have a photo function defined and pass the id of the photo to the function? 

[cyberRobot]

Are you able to show what the photo1(), photo2(), photo3() functions look like?

[black_pearl]

idk thats the way i learned it

but it works fine when i do it like this : echo $car[0]->photo1() or echo $car[0]->photo2() or echo $car[0]->photo3() ...

but idk how many pics the user will add (max is 8 photos per car) and i want to use the " for "

the problem is idk how to get it right echo $car[0]->photo . $i . "()"    this doesn't work it only does echo $car[0]->photo  thus gives me error i want to be able to send this echo $car[0]->photo1() with the $i

[black_pearl]

they r just returns : http://prntscr.com/7vbf1c

[scootstah]

This is the correct syntax for what you're trying to do:

<img onmouseover="preview.src=<?php echo $car[0]->{'photo' . $i}();?>.src"  src="<?php echo $car[0]->{'photo' . $i}()?>" alt=""/>

But, I agree with what other's have said: that's a really wacky way to go about things.

[black_pearl]

thank you very much scootstah and cyberRobot for the help it works now

 

i tried the code u gave scootstah and it works

but u said its a wacky way, how can i improve it how else can i do it ? 

i have learned that way thats why went for it

[cyberRobot]

For what it's worth, many of the methods could be replaced with a single method that returns the requested variable. Here's a quick example of the direction you could go:

<?php
//REPORT ALL PHP ERRORS
error_reporting(E_ALL);
ini_set('display_errors', 1);
 
 
class testClass {
    private $_portes = 'Portes';
    private $_photo1 = 'Photo1';
    private $_photo2 = 'Photo2';
    private $_photo3 = 'Photo3';
 
 
    public function getValue($variableName) {
        if(isset($this->$variableName)) {
           return $this->$variableName;
        }
    }
}
 
 
$car = new testClass;
echo '<div>' . $car->getValue('_photo1') . '</div>';
echo '<div>' . $car->getValue('_portes') . '</div>';

$i = 2;

echo '<div>' . $car->getValue("_photo$i") . '</div>';

?>

[scootstah]

I'd go for something like this:

class testClass

{

    private $photos;


    public function setPhotos(array $photos)

    {

        $this->photos = $photos;

    }


    public function getPhotos()

    {

        return $this->photos;

    }

}


$car = new testClass();

$car->setPhotos(array('photo1.jog', 'photo2.jpg', 'photo3.jpg'));


foreach ($car->getPhotos() as $photo) {

    echo '<img src="' . $photo . '" />';

}

[black_pearl]

wow that way would of save me a lot of time all the returns i wrote could be done with one function 

thanks to you guys now i know this way