Facebook like and share

[Ex1t]

This is my code for facebook like and share

<img src='<?php echo $path; ?>' height="500" width='500' alt='<?php echo $imgname; ?>' title='<div class="fb-like" data-href="http://mysite.com/<?php echo $path; ?>" data-layout="standard" data-action="like" data-show-faces="true" data-share="true"></div>'"></iframe>

Now $path is location to image, $imgname is name of image

When I look image for first time I can see like and share button, but when i do it again, i cant see like and share button.. Why?

[abrahamgarcia27]

maybe it has to do something with your $path variable. Can we see that? 

[Ex1t]

     <?php


          ....


          $sql="SELECT * FROM `images` ORDER BY `id` DESC LIMIT $start,$end";

          $rdata=mysqli_query($conn, $sql);

          while($res=mysqli_fetch_array($rdata))

          {

          $imgname=$res['image'];

          $path = 'img/'.$imgname;


          ?>


         <img src='<?php echo $path; ?>' height="500" width='500' alt='<?php echo $imgname; ?>' title='<div class="fb-like" data-href="http://site.com/<?php echo $path; ?>" data-layout="standard" data-action="like" data-show-faces="true" data-share="true"></div>'>


          <?php


          }



          ?>

 

[maxxd]

Couple things here. First and foremost, print the value of $path to screen - that way you can see (and show us) exactly what the variable $path contains.

 

Secondly, why are you trying to put a div in the title attribute of an image?

[Ex1t]

Because im using fancybox for zoom
When someone click on image, image zooms and title attribute is description or in my way like and share buttons

Edited August 10, 2015 by Ex1t

[RobertVecy]

I would have only been following the instructions for the facebook like button.But in hindsight, I would concur.

[satyapriya]

Its because of the file paths...check patiently..you will get the solution.