rvdveen27 Posted August 24, 2015 Share Posted August 24, 2015 Hello all, A friend made this query for me in order to get a part of my page working $queryCategory = "SELECT *,(SELECT dc.id FROM drive_cargotype dc, drive_routes dr WHERE dc.id = dr.cargotype AND dr.id=? ORDER BY dr.id DESC LIMIT 1) as cargo FROM drive_cargotype"; $stmt = $db->prepare($queryCategory); $stmt->execute(array($_GET['id'])); $categories = $stmt->fetchAll(); However, he didn't give me an explanation on how this query actually works. With my knowledge I understand some parts of it, but I don't know where to adapt the query so that it's also applicable for other sections of the page. Is there anyone who can help me put the above query to something I'm more used to? (Example below) (This query has nothing to do with previous query, it just shows how I'm used to doing queries and how I can actually understand it) SELECT dr.id ,u.username as 'driver' ,sloc.name as 'start' ,scom.name as 'startcompany' ,eloc.name as 'end' ,ecom.name as 'endcompany' ,cargoweight ,dc.name as 'cargo' ,dct.name as 'cargotype' ,time ,cargodamage ,drt.name as 'rating' ,distance ,price ,costs ,screenshot ,status ,price - costs - cargodamage as 'profit' FROM drive_routes dr INNER JOIN users u ON u.id = dr.driver LEFT JOIN users hb ON hb.id = dr.handledby INNER JOIN drive_locations sloc ON sloc.id = dr.start INNER JOIN drive_locations eloc ON eloc.id = dr.end INNER JOIN drive_companies scom ON scom.id = dr.startcompany INNER JOIN drive_companies ecom ON ecom.id = dr.endcompany INNER JOIN drive_cargo dc ON dc.id = dr.cargo INNER JOIN drive_cargotype dct ON dct.id = dr.cargotype INNER JOIN drive_rating drt ON drt.id = dr.rating WHERE dr.id = ". $_GET['id'] ." "; try { $stmt = $db->prepare($query); $result = $stmt->execute(); } catch(PDOException $ex) { die("Failed to run query: " . $ex->getMessage()); } $rows = $stmt->fetchAll(); $count = $stmt->rowcount(); Thanks so much in advance! Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/ Share on other sites More sharing options...
Barand Posted August 24, 2015 Share Posted August 24, 2015 Why would a friend do that to you? Have you upset him recently? Stick to your familiar joins and don't introduce subqueries with inefficient join syntax (... FROM A, B WHERE ...) Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519560 Share on other sites More sharing options...
rvdveen27 Posted August 24, 2015 Author Share Posted August 24, 2015 Why would a friend do that to you? Have you upset him recently? Stick to your familiar joins and don't introduce subqueries with inefficient join syntax (... FROM A, B WHERE ...) Lol no I did not upset him, he just has a different way of doing things. The whole idea was to create a query, that selects the correct option based on the information in the database. Which is something I now also need to apply for other selection fields. Here's the whole thing: $queryCategory = "SELECT *,(SELECT dc.id FROM drive_cargotype dc, drive_routes dr WHERE dc.id = dr.cargotype AND dr.id=? ORDER BY dr.id DESC LIMIT 1) as cargo FROM drive_cargotype"; $stmt = $db->prepare($queryCategory); $stmt->execute(array($_GET['id'])); $categories = $stmt->fetchAll(); Cargo type:<br /> <select name="cargotype" class="form-control"> <?php foreach($categories as $category): ?> <option value="<?=$category['id']?>" <?php if($category['cargo'] == $category['id']){echo "selected";}?>> <?=$category['name']?><option> <?php endforeach; ?> Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519563 Share on other sites More sharing options...
rvdveen27 Posted August 25, 2015 Author Share Posted August 25, 2015 So I had my own try at this query. This is how far I got: $query = " SELECT dr.id as 'id', name FROM drive_rating dr LEFT JOIN drive_routes dro ON dro.rating = dr.id WHERE dr.id=? "; try { $stmt = $db->prepare($query); $result = $stmt->execute(array($_GET['id'])); } catch(PDOException $ex) { die("Failed to run query: " . $ex->getMessage()); } $results4 = $stmt->fetchAll(); The idea that it gets all the "id" and "name" from the table "drive_ratings" and that it NEXT to that, also check which "id" in the table "drive_ratings" is equal to the "rating" in the table "drive_routes". I feel I'm only missing like one critical thing here but I can't put my finger on it. Anyone has any idea how to complete this query? Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519621 Share on other sites More sharing options...
Psycho Posted August 25, 2015 Share Posted August 25, 2015 Your explanation isn't very clear. It might help to show some sample data in those two tables and the expected results from the query. Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519623 Share on other sites More sharing options...
Barand Posted August 25, 2015 Share Posted August 25, 2015 Your attempt doesn't use the same tables SELECT dr.id as 'id', name FROM drive_rating dr LEFT JOIN drive_routes dro ON dro.rating = dr.id WHERE dr.id=? compared with SELECT *,(SELECT dc.id FROM drive_cargotype dc, drive_routes dr WHERE dc.id = dr.cargotype AND dr.id=? ORDER BY dr.id DESC LIMIT 1) as cargo FROM drive_cargotype"; Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519624 Share on other sites More sharing options...
rvdveen27 Posted August 25, 2015 Author Share Posted August 25, 2015 (edited) Correct. That's because my attempt is for the field "drive rating" in the form. The other query was for the field "cargo type" in the form. Here's extra clarification. Below is one row of data pulled from the database. The image below this, is the page that should fill the <form> fields with the information that is in the database as stated above. The blue field is the field that actually goes correctly. The <option> selected in the <form> on this page, is correct info from the database. The red fields are fields that I still need to fix with a (similar) query. Currently it just selects the first <option> in the list. I want it to select ( "selected") the same value as the one that's said in the database (the row of data I provided). Edited August 25, 2015 by rvdveen27 Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519625 Share on other sites More sharing options...
rvdveen27 Posted August 25, 2015 Author Share Posted August 25, 2015 First image provided was incorrectly, here's the correct one: You can see that the blue fields match in both pictures (thanks to that query), while the red fields do not and should be matching. Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519626 Share on other sites More sharing options...
rvdveen27 Posted August 26, 2015 Author Share Posted August 26, 2015 More experimenting with my query gets me the following. SELECT dr.id as 'id', name, dro.rating FROM drive_rating dr LEFT JOIN drive_routes dro ON dro.rating = dr.id Which results in: And when I add the WHERE to the query: SELECT dr.id as 'id', name, dro.rating FROM drive_rating dr LEFT JOIN drive_routes dro ON dro.rating = dr.id WHERE dro.id = 539 It results in: It's slowly getting there. But it's still not what I want it to do. Anyone has any idea how to get this right? Again. I want it to get all the entries from "id" and "name" from the table "drive_ratings" while also checking which "id" in the table "drive_ratings" matches the "rating" in the table "drive_routes". Quote Link to comment https://forums.phpfreaks.com/topic/297915-help-with-query/#findComment-1519669 Share on other sites More sharing options...
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