Drezard Posted December 9, 2006 Share Posted December 9, 2006 Hello, Heres my class with all my functions:[CODE]<?phpsession_start();error_reporting(E_ALL);class web { var $connection = NULL; var $login = NULL; var $dbhost = "localhost"; var $dbuser = "test"; var $dbpass = "test"; var $db = "sellyourownhome"; function connect() { $this->connection = mysql_connect($this->dbhost, $this->dbuser, $this->dbpass) or die ("Unable to connect!"); mysql_select_db($this->db) or die ("Unable to select database!"); } function close_connect() { mysql_close($this->connection); } function check_user() { if (!isset($_SESSION['userinfo'])) { $this->login_box(); } if (isset($_SESSION['userinfo'])) { $this->connect(); $userinformation = explode(" ", $_SESSION['userinfo']); $user = $userinformation[0]; $pass = $userinformation[1]; echo $user; echo $pass; $query = "SELECT * FROM users WHERE user='$user' AND pass='$pass'"; $result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); $count = mysql_num_rows($result); if ($count == 1) { $this->login = 1; } if ($count == 0) { echo "ERROR: Session has corrupted. Please logout and relogin"; $this->login = 0; } } } function add_user() { if (isset($SESSION['userinfo'])) { $this->check_user(); } if (!isset($_SESSION['userinfo'])) { $this->connect(); if (!isset($_POST['user'])) { echo "<form action='' method='post'> Username: <input type='text' name='user'> Password: <input type='password' name='pass'> Comfirm Password: <input type='password' name='pass2'> Email: <input type='text' name='email'> Comfirm Email: <input type='text' name='email2'> <input type='submit' name='submit'> </form>"; } if (isset($_POST['user'])) { $user = $_POST['user']; $pass = $_POST['pass']; $pass2 = $_POST['pass2']; $email = $_POST['email']; $email2 = $_POST['email2']; $priv = $_POST['priv']; if ($pass == $pass2) { if ($email == $email2) { $query = "SELECT * FROM users WHERE user='$user' AND pass='$pass'"; $result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); $count = mysql_num_rows($result); if ($count == 1) { echo "Username already created"; } if ($count == 0) { $query = "INSERT INTO users (user, pass, priv) VALUES ('$user', '$pass', '2')"; $result = mysql_query($query) or die ("Error in query: $query."); $query = "INSERT INTO profiles (user, email) VALUES ('$user', '$email')"; $result = mysql_query($query) or die ("Error in query: $query."); echo "Acount sucessfully created"; } } else { echo "Emails dont match"; } } else { echo "Passwords dont match"; } } } } function login_box() { $this->connect(); if (isset($_SESSION['userinfo'])) { $this->check_user(); $userinformation = explode(" ", $_SESSION['userinfo']); $user = $userinformation[0]; echo 'Welcome, $user'; } if (!isset($_SESSION['userinfo']) && !isset($_POST['user'])) { echo "<form action='' method='post'> Username: <input type='text' name='user'> Password: <input type='password' name='pass'> <input type='submit' name='submit'> </form>"; } if (!isset($_SESSION['userinfo']) && isset($_POST['user'])) { $user = $_POST['user']; $pass = $_POST['pass']; $query = "SELECT * FROM users WHERE user='$user' AND pass='$pass'"; $result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); $count = mysql_num_rows($result); if ($count == 1) { $_SESSION['userinfo'] = '$user $pass'; echo "Sucessfully logged in"; } if ($count == 0) { echo "Username or password are incorrect."; } } } function logout() { if (!isset($_SESSION['userinfo'])) { echo "You have to be logged in to view this."; } if (isset($_SESSION['userinfo'])) { session_destroy(); echo "You have sucessfully logged out"; } } }?>[/CODE]Alright so with the function check_user(); it doesnt explode the session properly. The variables $user and $pass are empty. Whats wrong with it?The whole code is there so you should be able to see that the function login_box sets the session and i want check_user to read it but it doesnt.- Cheers, Daniel Quote Link to comment Share on other sites More sharing options...
esukf Posted December 9, 2006 Share Posted December 9, 2006 Try changing the line $_SESSION['userinfo'] = '$user $pass';to $_SESSION['userinfo'] = "$user $pass"; //use double quotes instead of single Quote Link to comment Share on other sites More sharing options...
sylesia Posted December 9, 2006 Share Posted December 9, 2006 A few things to try, first off, I am pretty sure if you do it the way you are, you need it to look like$_SESSION['userinfo'] = $user . " " . $pass; // Took out quotes and added a period which binds them together with the spaceCould have two variables if that does not work, a user and pass variableTell me what happens if you do the period one though, that should help you in what you need Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted December 9, 2006 Share Posted December 9, 2006 The code[code]<?php$some_var = "$var1 $var2";?>[/code]and the code[code]<?php$some_var = $var1 . ' ' . $var2;?>[/code]produce the same result. Try it yourself.Ken Quote Link to comment Share on other sites More sharing options...
Drezard Posted December 10, 2006 Author Share Posted December 10, 2006 The double quotes worked. Thanks for the help.- Cheers, Daniel Quote Link to comment Share on other sites More sharing options...
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