Help with json_decode

[KingNeil]

I am using Javascript to encode data with json... and using PHP to decode this data with json_decode();

 

My JSON looks like this:

 

{"0":{"url":"http://www.businessinsider.com/mark-zuckerberg-mandarin-lunar-new-year-video-2016-2#BusinessInsider","title":"Mark Zuckerberg shows off his Mandarin skills to wish a healthy and prosperous Year of the Monkey","source":"http://www.businessinsider.com","timestamp":1454909507},"1":{"url":"http://uk.businessinsider.com/mark-zuckerberg-mandarin-lunar-new-year-video-2016-2#BusinessInsider","title":"Mark Zuckerberg shows off his Mandarin skills to wish a healthy and prosperous Year of the Monkey","source":"http://uk.businessinsider.com/tech","timestamp":1454921864}

 

 

When I do json_decode, it doesn't work

 

The reason why, is because of the "0":, "1": etc

 

Usually, json is not encoded with {"0":{"url":"http://www.businessinsider.com

 

but rather, just {"url":"http://www.businessinsider.com

 

without the "{0":

 

What is your solution for this??

 

Can PHP decode the "{0":

 

Or, is the solution to strip the "{0": altogether...? If so, how would I do this?

 

Thanks

Edited February 8, 2016 by KingNeil

[QuickOldCar]

Try using http://jsonlint.com/ and validate your json

[kicken]

The "0": and "1": are there because you encoded an array-like object. Such json is perfectly valid, and would decode just fine with json_decode. You'll probably want to pass the $assoc flag as true so it decodes to an array rather than an object, that will make accessing things easier.

 

$array = json_decode($json, true);
var_dump($array[0], $array[1]);