using Strrchr to get end of string

[mallen]

I'm trying to take the value and pick out everything after the trailing slash. I tested and the variable is correct. On the third line I can't figure out how to format it.

var_dump($image);// http://somewebsite.com/images/image1.jpg

var_dump(substr(strrchr('http://somewebsite.com/images/image1.jpg', '/'), 1)); //image1.jpg

var_dump(strrchr(strrchr('$image','/'),1));//getting false

[cyberRobot]

If you want to use a variable, it can't be in a single-quoted string. Try

var_dump(strrchr(strrchr($image,'/'),1));

[mallen]

I am getting boolean false

[cyberRobot]

Ah...the function calls are backwards. Try

var_dump(substr(strrchr($image,'/'),1));

Sorry, not backwards. You were calling strrchr() twice.

Edited March 24, 2016 by cyberRobot

[mallen]

Yes still getting boolean false

[cyberRobot]

For what it's worth, this worked for me:

<?php
var_dump(substr(strrchr('http://somewebsite.com/images/image1.jpg', '/'), 1));
 
$image = 'http://somewebsite.com/images/image1.jpg';
var_dump($image);
var_dump(substr(strrchr($image,'/'),1));
?>

[mallen]

Ok I am following you. But in your example you assigned a value to $image.  But I already have a value to $image. And if I dump it is gives me the string. So I need to do the reverse.

$image = 'http://somewebsite.com/images/image1.jpg';

[cyberRobot]

Ok I am following you. But in your example you assigned a value to $image.  But I already have a value to $image. And if I dump it is gives me the string. So I need to do the reverse.

 

I just added the $image variable to test the code.

 

What does your current code look like? Note that you'll want to make sure that strrchr() isn't being called twice and the $image variable isn't enclosed with single quotes. Could you also post the line that defines $image?

[mallen]

$THEURL = "SELECT Image_URL From ... ect";//the query


$image = $wpdb->get_row($THEURL, ARRAY_A);//the variable is dynamic


var_dump(substr(strrchr($image,'/'),1)); fails


var_dump(substr(strrchr('http://somewebsite.com/images/image1.jpg','/'),1)); gives 'image1.jpg'


var_dump($image); //  gives 'http://somewebsite.com/images/image1.jpg'

I figured it out:


var_dump(substr(strrchr($image['Image_URL'],'/'),1));

Edited March 24, 2016 by mallen

[cyberRobot]

Does $wpdb->get_row() return a string...or some other type of variable like an array or object? What is the exact output of

var_dump($image);

It should look something like this, if it's a string:

string(40) "http://somewebsite.com/images/image1.jpg"

Also, is PHP set to display all errors and warnings? Note that you can add the following to the top of your script during the debugging process:

<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
?>

[cyberRobot]

I figured it out:

var_dump(substr(strrchr($image['Image_URL'],'/'),1));

 

I'm glad you figured it out. 

 

Note that I marked the topic as solved. If you need anything else, you can start a new topic...or mark this one as unsolved (if it's directly related).