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Using urlencode()


Go to solution Solved by Jacques1,

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I wish to urlencode part of a URL, and can do the following:

sendIt("/cars/".urlencode("Model T"));
function sendIt($u)
{
   $ch = curl_init("http://forums.phpfreaks.com{$u}");
}

Instead, I wish to put the urlencode statement in the function as follows.

sendIt("/cars/Model T");
function sendIt($u)
{
   $ch = curl_init("http://forums.phpfreaks.com".urlencode($u));
}

Problem is that it encodes the forward slashes.

 

How can this be done?

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https://forums.phpfreaks.com/topic/301395-using-urlencode/
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  • Solution

The second code snippet doesn't make a lot of sense, because you're blindly applying urlencode() to a complete part of the URL. This will not only fudge up forward slashes. A query or fragment will also be affected.

 

You need to apply the encoding while you assemble the URL or URL part so that you know exactly what you encode (e. g. an individual path segment or parameter).

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https://forums.phpfreaks.com/topic/301395-using-urlencode/#findComment-1534011
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