problam using $_POST

[Accurax]

Was having some problems getting this posted..... please find the question in the next post..... really appreciate any help on this guys

[Accurax]

I'm pretty sure im doing something pretty thick here, but could someone take a lok please?

heres my form to select the picture

[code]
<form enctype="multipart/form-data" method="POST" action="uploadprocess.php">

<input type="hidden" name="MAX_FILE_SIZE" value="15000000">

Choose file to send: <input type="file" name="filename"> and <input type="submit">

</form>[/code]and heres the php page that proccesses it:

[code]
<?php
$filepath = $_POST['filename'];
echo $filepath;

      $source = "pictures";
      move_uploaded_file($_FILES['filename']['tmp_name'],
              "../...../........./$source/".$_FILES['filename']['name']);


?>[/code]
The problem is that i cant seem to get the $_POST['filename'] variable to work, This variable should be the path to and filename of the uploaded picture, and the aim is really to get this value stored into my database for later use, for now i guess i just need to get the value passing properly, any idea's guys?

[Accurax]

<cut>

[fearmyride]

Try this


if (isset($_POST['submit'])) {
 
//check for the file upload
if (is_uploaded_file ($_FILES['filename']['tmp_name'])) {
  if (move_uploaded_file ($_FILES['filename']['tmp_name'],"../pictures/{$_FILES['filename']['name']}")) {
   
    echo '<p>The file has been uploaded</p>';
} else {
  echo '<p><font color="red">the file did not upload</font></p>';
$image = '' ;
exit;
}

}

[JasonLewis]

wow whats with all the ../............../............................../ lol. that wouldnt do crap all. ../ would take you to the parent but i dont think ................./ does anything.

but anyways. what fearmyride looks good for me.

[fearmyride]

i think he used the dots instead of the folder name because you're right it will do nothing i believe

[Accurax]

thats right, im over cautios about posting lol

[Accurax]

[quote author=fearmyride link=topic=118170.msg482580#msg482580 date=1165838259]


Try this


if (isset($_POST['submit'])) {
 
//check for the file upload
if (is_uploaded_file ($_FILES['filename']['tmp_name'])) {
  if (move_uploaded_file ($_FILES['filename']['tmp_name'],"../pictures/{$_FILES['filename']['name']}")) {
   
    echo '<p>The file has been uploaded</p>';
} else {
  echo '<p><font color="red">the file did not upload</font></p>';
$image = '' ;
exit;
}

}
[/quote]


How do i get the path to the stored file out of this?...... i need to write this info into my database so i can call the image whenever i need

[Accurax]

my above script works perfectly... (ignoring security) .. all im trying to do is get the path to the moved file into a variable so i can put it in my database

[JasonLewis]

make the variable before using move_upload_file.

[code=php:0]
$image_var = "../pictures/{$_FILES['filename']['name']}";
[/code]

then in move_uploaded_file:
[code=php:0]
move_uploaded_file ($_FILES['filename']['tmp_name'],$image_var)
[/code]

then in the success add the link to the database.

[fearmyride]

try making a $var like this after the file is uploaded :

$var = "../foldername/$_FILES['filename']['name'];

and then query the $var by inserting into the database

[JasonLewis]

why not before, like i suggested? :P
oh and just so you no. your code will throw an error. you didnt close the " and you can have arrays in a normal string. wrap it in {}. :P

[Accurax]

None of that works guys.......... all i want to do is this

1) Move the uploaded file from the tmp folder to a permanent folder on my webserver...... Complete

2) Identify the precise path to this Moved file and store it in a a mysql database

I know that tis information is there.... i just cant get it out in a way that makes sense as to how im going to then write this into my database ......... what stores the path + file name .... i know the filename is stored in $_FILES['userfile']['name']; and as such ;

$filename = $_FILES['userfile']['name'];

should assign the file name to the variable $filename ..... i honestly couldnt tell you if it actually does, becauyse at the moment i cant even get the damnd thing to echo out correctly , and whilst i do really, honestly truly appreciate your posts, i am in fact confused as to how they address this issue.

Please can anyone actually explain how i do this..... im about to throw things around, and my cat looks terrified :p

[fearmyride]

[quote author=ProjectFear link=topic=118170.msg482606#msg482606 date=1165840307]
why not before, like i suggested? :P
oh and just so you no. your code will throw an error. you didnt close the " and you can have arrays in a normal string. wrap it in {}. :P
[/quote]

before after tomorrow :) good point about using {} it's typo that will create an error

[Accurax]

Can someone please help me here

[Accurax]

Im trying this.... basically my theory is that if i can get a variable to echo what i want, then i should then be able to simply slap that variable in my database and voilla.

<?php
$filepath = "/pictures/".$_FILES['filename'];
echo $filepath;

      $source = "pictures";
      move_uploaded_file($_FILES['filename']['tmp_name'],
              "../webserver/mysite/$source/".$_FILES['filename']['name']);


?>

The file uploads without a problem .... but the echo statement gives me the following;

/pictures/Array

Which is not what i want .........  :(

[HuggieBear]

If you're only uploading one file at a time, then surely this will work?

[code]<?php
$filepath = "/pictures/".$_FILES['filename']['name'];
echo $filepath;

      $source = "pictures";
      move_uploaded_file($_FILES['filename']['tmp_name'],
              "../webserver/mysite/$source/".$_FILES['filename']['name']);


?>[/code]

Regards
Huggie

[Accurax]

I now feel like a right muppet....... i had:

$filepath = "/pictures/".$_FILES['filename'];

and i needed:

$filepath = "/pictures/".$_FILES['filename']['name'];

i think im going to go and cry in the corner for a while......... thanks for all the help guys ........  :)

[HuggieBear]

No problem...

The word 'array' in the path should have given it away.

Regards
Huggie

[JasonLewis]

alright so you are doing what i or fearmyride suggested by making a variable with the path and the $_FILES['userfile']['name']. that should make a variable wiht a link like:
[code]../images/users/myimage.jpg[/code]

which you could then insert into the database. but your saying its not working.
well. before the if(move_upload_file... blah blah blah make the variable like is suggested.
then immediatly below it echo it out:

[code=php:0]echo $var;[/code]
then exit it.
[code=php:0]exit();[/code]

that should echo out the file name. if nothing is happening post it here... :)