CyberShot Posted June 17, 2017 Share Posted June 17, 2017 I am only able to get the value from the first index and I don't know what I am doing. I have an array that returns this when I dump the varaiable array(1) { [0]=> array(5) { ["title"]=> string(12) "Social links" ["facebook"]=> string(23) "http://www.facebook.com" ["twitter"]=> string(22) "http://www.twitter.com" ["google"]=> string(0) "" ["dribble"]=> string(0) "" } } I tried to echo the values like so. if( !empty($social[0]['facebook')){ echo ' <li><a href="' . $social[0]['facebook'] . '"><img src="' . get_template_directory_uri() . '/images/icons/icon2.gif"><img src="'. get_template_directory_uri() . '/images/icons/icon2_active.gif" class="img_act"></a></li>'; } if( !empty($social[1]['twitter'])){ echo ' <li><a href="' . $social[1]['twitter'] . '"><img src="' . get_template_directory_uri() . '/images/icons/icon1.gif"><img src="'. get_template_directory_uri() . '/images/icons/icon1_active.gif" class="img_act"></a></li>'; } if( !empty($social[2]['google'])){ echo ' <li><a href="' . $social[2]['google'] . '"><img src="' . get_template_directory_uri() . '/images/icons/icon3.gif"><img src="'. get_template_directory_uri() . '/images/icons/icon3_active.gif" class="img_act"></a></li>'; } if( !empty($social[3]['dribble'])){ echo ' <li><a href="' . $social[3]['dribble'] . '"><img src="' . get_template_directory_uri() . '/images/icons/icon4.gif"><img src="'. get_template_directory_uri() . '/images/icons/icon4_active.gif" class="img_act"></a></li>'; } It only returns the first value in the array. EDIT.... I just figured it out. instead, Is there a more eloquent way of doing this? Link to comment Share on other sites More sharing options...
gizmola Posted June 17, 2017 Share Posted June 17, 2017 We'd need to see your code. Given the variable you dumped everything would have been: echo $social[0]['title']; echo $social[0]['facebook']; //etc If the annoyance is that you have a useless array element, you could do this: $social = $social[0]; Then you'd just reference the associative elements by key. echo $social['twitter']; With that said, foreach() loops are helpful: foreach ($social[0] as $key => $value) { echo "$key = $value </br>"; } Link to comment Share on other sites More sharing options...
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