array_filter not === with $varible only with text entry

[DaveSandwich]

 Im trying to filter and return all that matches iphone with iphone.

 

If i type "iphone" (see typed example below) it works fine but if i put a variable it which is $variphone it dont, even though they are both the same.

 

 

 

typed example:

$filtermodel = array_filter($modelfilter, function( $data ){
		return $data['0'] == "Iphone"; //case sensitive entry

variable example

$filtermodel = array_filter($modelfilter, function( $data ){
		return $data['0'] == $variphone; //case sensitive entry

var_dump $variphone

string(5) "Iphone"

var_dump - typed example:

array(1) {
  [2]=>
  array(7) {
    [0]=>
    string(4) "Iphone"
    [1]=>
    string(5) "Iphone 8"
    [2]=>
    string(7) "17 - 17"
    [3]=>
    string(3) "500"
    [4]=>
    string(9) "black"
    [5]=>
    string(94) "32gb"
    [6]=>
    string(94) "32gb"
  }
}

var_dump - variable example

array(0) {
}

[ignace]

$search = function($array, $input) {

  return array_filter($search, function($phone) use ($input) {

    return $phone[0] == $input ? true : false;

  });

};


$result = $search($modelfilter, $variphone);


var_dump($result);

[kicken]

variable example

$filtermodel = array_filter($modelfilter, function( $data ){
		return $data['0'] == $variphone; //case sensitive entry

 

You're not showing $variphone being defined there anywhere. If it's not defined within your function then it won't exist. PHP doesn't inherit variables from outer scopes automatically like some other languages. You can import variables you need using a use statement, as demonstrated in ignace's example.