Image print help in Php

[s4salman]

I want to print image in the following Php code along with the name of the image. I want to print name in first row of the html table, while full image in the 2nd row. row[5] contain image file name such as abc.jpg. I want to print whole image url like this in second row:

https://xyz.com/po/row[5]

Can any body help me how i can do this. I tried different code but could not succeed.

 

<?php
$con=mysqli_connect("localhost","****","****","s4salman_color");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$url = $_GET['url'];

$sql="SELECT * FROM coloringpages where url = '$url' ORDER BY id";

if ($result=mysqli_query($con,$sql))
  {
  // Fetch one and one row
  while ($row=mysqli_fetch_row($result))
    {
    printf ("%s (%s)\n",$row[0],$row[5]);
    }
  // Free result set
  mysqli_free_result($result);
}

mysqli_close($con);
?>

 

Edited June 5, 2018 by Barand

[Barand]

To display an image you need to use an html <img> tag EG

echo "<img src='path/to/image' >"

 

[dalecosp]

It might also be wise to redact (that is, remove or obfuscate/cover-up) your DB credentials in your example code's mysqli_connect() function. ?

[Barand]

Done.