passing variable from command line?

[swellinfo]

I'm wondering how or if you can pass a variable to a php script from the command line. 

So, I'd like to pass the dynamic variable $pre = "wna"; to the command line before I process my script.

Any help here? 

Thanks. 

[AV1611]

not sure what you mean...

you mean like exec('wna');?

[swellinfo]

no, I'd like to define a variable ($pre) outside of the script. 

So, where I am executing my script from a linux command line:
php myscript.php

Is there a way to pass a variable to the script from the command line, or do I just need to create another file, and do an include?

[swellinfo]

I figured this out:

Passing variables on the command line is different than from a url, where you would type

http://www.domain.com/myscript?var=whatever

instead, on the command line, you type

php myscript.php whatever     

you put a space in between the script and the value you are passing, and that value is available in the $argv variable.
$argv is an array, and the first value is always the name of the script, and in this example case the second value would be "whatever". 
- $argv[1] = "whatever". 

[Daniel0]

More info here: http://php.net/features.commandline

[AV1611]

replay I suppose you could also run another script that create a text file then parse the text file if you need to send more complicated stuff to the command line...

Huh?

Can PHP read an environment variable from the system?