PLease Help me in this Error

[Ehsan_Nawaz]

<?php
require("config/config.php");
if(isset($_SESSION['username'])){
    
    $userLoggedIn = $_SESSION['username'];
    $user_detail = mysqli_query($con, "SELECT * FROM users WHERE username='$userLoggedIn'");
    $user = mysqli_fetch_array($user_detail);
    echo $user['First_Name'];
}    
?>

In the Same Page

line:33 -->     <?php echo $user['First_Name']?>

When i execute my code i show the error

Notice: Undefined variable: user in C:\xampp\htdocs\social\include\header.php on line 33

 

[Barand]

Before you can use $_SESSION you must call "session_start()".

Put it at the start of the code.

[Ehsan_Nawaz]

WHEN I START SESSION ERROR SHOW ME SESSION_START() (A SESSION HAD ALREADY BEEN STARTED)

[Barand]

No need to shout. It must be in your config file (but we can't possibly know that)

[cyberRobot]

18 hours ago, Ehsan_Nawaz said:

When i execute my code i show the error

Based on the code provided, $user is only being set if the SESSION variable for "username" is set. If you haven't already, I would check to see what that SESSION variable contains when you're getting the error.

It's difficult to tell how you should proceed with the information provided. In the end, you'll likely need to test whether $user is set before trying to use it. How you do that depends on the purpose of the page and how your script is set up.

[Psycho]

Try putting this bit of debugging code in your script right before your if() statement.  What does it produce when you run the script?

if(!isset($_SESSION))
{
    echo "Session was not started yet";    
}
else
{
    echo "Session data:<br>";
    echo "<pre>".print_r($_SESSION, true)."</pre>";
}

 

[Ehsan_Nawaz]

Here is the config file code

 

<?php
ob_start();
session_start();
$timeOne = date_default_timezone_set("Europe/London");
$con = mysqli_connect("localhost","root","","social");
if(mysqli_connect_errno()){
    echo"Filled to connect";
}
?>