Inserting multiple values for one user in new column

[PNewCode]

Hello. It's been a while since I've been here and I hope everyone is doing well. 
My task that I'm taking on is adding a value to all entries based on username. I added the new column and need to add that in for a different project. But I haven't started the other one yet because I need to get this done first.
I tried to google this and I keep getting results that aren't what I need (IE How to insert multiple rows, or how to replace values in phpmyadmin, etc)

To be more specific, lets say user "joe" has 200 entries.
Joe is a user that has a reqid that is the number 75
Now I've added the column "reqid"
I need to add the number 75 in the column reqid, to all the entries made be Joe

The column is INT(255)

Note: Each user has a different name, and I already have a working way to add the reqid to the database from this point on. So what I need to do is edit all the past entries before today with their reqid's

I don't have anything that I have tried because I'm running in circles on what to do. If anyone has an example script that will get me in the right direction, or a link where I can see how this is done, I would appreciate it so very much.

Note 2: Ultimately I would like to make a form where I can just search a name and add that in for all of that users entries, but if this can be done in phpmyadmin in a batch update that will work too (the search doesn't seem to allow to replace just one user to change (example 0 to 75)
 

[kicken]

Sounds like you just want an update query.  For example

update users_table
set
   reqid=75
where
   username='joe'
   

If that's not what you want, then you may need to try and explain again differently.

[PNewCode]

19 minutes ago, kicken said:

update users_table
set
   reqid=75
where
   username='joe'

This looks like what I need. So below is what I made, though all of the colums with the name JOE still shows  zero. I'll add a screen shot
Note: Joe was just an example. In the screen shot below, I'm attempting to update all that has the name "MetalHead" with "75"
 

<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');



	$servername = "removed for posting";
	$username = "removed for posting";
	$password = "removed for posting";
	$dbname = "removed for posting";

$sql = "SELECT * FROM nametable";



$sql= "UPDATE nametable SET reqid= '75' WHERE name='MetalHead' ";

?>

The screen shot of the DB

EDIT: No errors are showing on the screen

Edited December 5, 2023 by PNewCode

[PNewCode]

@kicken WOW I can't believe I didn't make the DBconnection hahaha. Okay, so with your answer and adding the DB connection it works. Thanky you so much!

 

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

$sql = "UPDATE nametable SET reqid='75' WHERE name='MetalHead'";

if ($conn->query($sql) === TRUE) {
  echo "Record updated successfully";
} else {
  echo "Error updating record: " . $conn->error;
}

$conn->close();

 

[Barand]

The correct way to do it is use a JOIN in a query when you need the reqid, not to duplicate values from one table into another.