willl Posted January 14, 2006 Share Posted January 14, 2006 Hello, I hope someone knows what this problem might be; I have designed and built a website and tested the php/mysql code using phpdev which simulates an apache/mysql/php server using the localhost on my pc. All the queries work perfectly, however I have just uploaded my site to the actual webserver and most of the queries are returning empty result sets! It's like they are there because for instance; a while ($row = mysql_fetch_array.... does return the correct amount of rows! One while loop I have wrapped each result in a div and u can just see empty divs for the right amount of rows!! Another example: I have a database of keywords, a while loop prints each keyword seperated by a comma - the right amount of commas are there! This is an example of a code that is returning empty sets: $query = "SELECT * from company_ins, company_log WHERE company_ins.ins_id = '$typeid' AND company_log.Id = company_ins.company_Id order by company_log.name"; $result = mysql_query($query, $conn); while ($row = mysql_fetch_array($result, $conn)) { if ($row['type_featured'] != 'f') { ?> <div class="linkbox"> <a href="<?php echo $row['link']; ?>" class="link" target="_blank"><strong><?php echo $row['name']; ?></strong></a> <p><?php echo $row['description']; ?></p> <p><a href="<?php echo $row['link']; ?>" target="_blank"><?php echo $row['link2']; ?></a></p> </div> <?php } } ?> I just thought - do you think I need to be using an INNER JOIN select query here? Any thoughts? Thanks! Will Quote Link to comment Share on other sites More sharing options...
willl Posted January 14, 2006 Author Share Posted January 14, 2006 I was using incorrect mysql_fetch_array syntax. (Should not have included $conn) Quote Link to comment Share on other sites More sharing options...
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