[SOLVED] A syntax error in a foreach statement

[swatisonee]

Hello,

I have the foll. code. The print_r(($array)); lines throws up the data correctly, but the foreach statement thereafter gives me an error ,line 32 being the foreach statement.

Would someone be able to guide me on the correct syntax ? Thanks ! Swati


[quote]
Parse error: syntax error, unexpected T_IS_GREATER_OR_EQUAL, expecting ')' in /home/easte9/public_html/egor/group5.php on line 32
[/quote]

[code]

$group = $_POST["group"];

$customer = $_POST["customer"];// this comes from  multiple checkboxes on a previous page

$array = implode(",", $customer);

print_r(($array)); // prints values correctly

foreach ($array as $key>= $value)      // this line is where the error is
{

$sql = "UPDATE  `Customers` SET `CGID` = $group WHERE `CID` = '$value'";
// echo $sql;
//each record having value of $array, like say 1,10,25 (that is $value)  etc needs to get updated with the $group figure

$result = mysql_query($sql);

  echo "Information Updated" ;
}
[/code]

[effigy]

[tt]$key>= $value[/tt] should be [tt]$key => $value[/tt].

[swatisonee]

I tried that but too it just prints the values but the sql statement does not get processed.

[printf]

You convert the $_POST array [b]customer[/b] to a [b]string[/b] using [b]$array = implode()[/b], so the foreach() will not work even after fixing [b]>=[/b]!

this...


[code]foreach ($array as $key>= $value)      // this line is where the error is
{[/code]


should be...

[code]foreach ( $_POST['customer'] as $key => $value )      // this line is where the error is
{[/code]


printf

[swatisonee]

Hi Printf, that worked great and thank you but i did not understand the logic.

since $array is giving me the individual values of 1,10 , 15, shouldnt the foreach take those values forward ?

Thanks.Swati