jstgermain Posted January 10, 2007 Share Posted January 10, 2007 ok, i will provide a few things so that someone may be able to help with what i am trying to do. here is my MySQL setup for the table that contains the info that I am trying to retrieve.-- -- Table structure for table `Menu`-- CREATE TABLE `Menu` ( `id` int(25) NOT NULL auto_increment, `name` varchar(100) default NULL, `l_name` varchar(100) default NULL, `content` text, PRIMARY KEY (`id`)) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;-- -- Dumping data for table `Menu`-- INSERT INTO `Menu` VALUES (1, 'Home', 'Home', 'Home page info here.);INSERT INTO `Menu` VALUES (2, 'Hosting', 'Hosting', 'Put hosting info here');INSERT INTO `Menu` VALUES (3, 'Contact Us', 'ContactUs', 'Put contact info here');here is the php i am currently using.[code]<?php #menu.php//Link 1 query$query1 = "SELECT * FROM Menu WHERE id=1"; $link1 = mysql_query ($query1);$l1 = mysql_fetch_array ($link1, MYSQL_ASSOC); //Link 2 query$query2 = "SELECT * FROM Menu WHERE id=2"; $link2 = mysql_query ($query2);$l2 = mysql_fetch_array ($link2, MYSQL_ASSOC); //Link 3 query$query3 = "SELECT * FROM Menu WHERE id=3"; $link3 = mysql_query ($query3);$l3 = mysql_fetch_array ($link3, MYSQL_ASSOC); ?><!--// This is where I display the links //--><a href="index.php?page=<?php echo $l1['l_name']; ?>"><?php echo $l1['name']; ?></a><a href="index.php?page=<?php echo $l2['l_name']; ?>"><?php echo $l2['name']; ?></a><a href="index.php?page=<?php echo $l3['l_name']; ?>"><?php echo $l3['name']; ?></a>[/code]as you can see, i am having to query the database 3 differnt times to make each link url and name display, and that is sort of a pain in the butt, and i am sure there is a better and easier way to do this. hopefully someone can help me shorten this task. keep in mind that there will be more than 3 links. there are just 3 right now since i am still in the testing phase of everything. any help will be greatly appreciated. thanks in advance. Link to comment Share on other sites More sharing options...
micah1701 Posted January 10, 2007 Share Posted January 10, 2007 [code]$query = "SELECT * FROM Menu WHERE id=1 OR id=2 OR id=3"; $link = mysql_query ($query3);$l= mysql_fetch_array ($link);<a href="index.php?page=<?php echo $l['l_name'][0]; ?>"><?php echo $l['name'][0]; ?></a><a href="index.php?page=<?php echo $l['l_name'][1]; ?>"><?php echo $l['name'][1]; ?></a><a href="index.php?page=<?php echo $l['l_name'][2]; ?>"><?php echo $l['name'][2]; ?></a>[/code]does that help? Link to comment Share on other sites More sharing options...
jstgermain Posted January 10, 2007 Author Share Posted January 10, 2007 that might, i will try it in a bit. need to finish this asp / js project at work first. i will let you know if it works or not. i am sure it will, but for some reason i just couldnt think of it. :p head hurts with all these projects. :S thanks. Link to comment Share on other sites More sharing options...
jstgermain Posted January 10, 2007 Author Share Posted January 10, 2007 no, didnt work. just displays the first 3 letters od the first row in the link name. :S the link name and name of the riste row is "Home", so the first like shoed up as "H", link two showed as"o", and link 3 showed as "m". :S so, the wuery itself looks ok, but the way you are calling the link with the [[b]0[/b]], [[b]1[/b]], and [[b]2[/b]] isnt correct. need another way to tell it the row. let me know if you think of something else. thanks Link to comment Share on other sites More sharing options...
jstgermain Posted January 11, 2007 Author Share Posted January 11, 2007 sorry to bump this, but it is at the bottom of the second page now, and i still need help if possible. please le tme know if anyone else can figure this out. Link to comment Share on other sites More sharing options...
jstgermain Posted January 11, 2007 Author Share Posted January 11, 2007 nvm everyone. got it working. got help from a friend. here is the code in case anyone else is ever needing to do something similar[code]<?php#menu.php$sql = "SELECT * FROM `Menu`"; $result = mysql_query($sql); while ($row = mysql_fetch_assoc($result)) { $id = $row['id']; // get the row id $link[$id]['name'] = $row['name']; // put in an array $link[$id]['l_name'] = $row['l_name']; // put in an array $link[$id]['content'] = $row['content']; // put in an array }?><!--// Links code //--><a href="index.php?page=<?php echo $link['1']['l_name']; ?>"><?php echo $link['1']['name']; ?></a><a href="index.php?page=<?php echo $link['2']['l_name']; ?>"><?php echo $link['2']['name']; ?></a><a href="index.php?page=<?php echo $link['3']['l_name']; ?>"><?php echo $link['3']['name']; ?></a>[/code]Just add as many links as needed. Link to comment Share on other sites More sharing options...
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