dennisbillings Posted February 27, 2006 Share Posted February 27, 2006 I want to make the following form set as a variable I can't get it to work and was hoping someone could give me a hand. The while loop is giving me headaches via parse errors and I can't figure out why. Any help would be greatly appreciated$form .= "<fieldset><form method=\"post\" action=\"<?php echo {$_SERVER['PHP_SELF']};?>\"onsubmit=\"return validate(uname,pass,pass1,fname,lname,email);\"><legend>User Registration: </legend><table><tr><td>Login Name:</td><td> <input type=\"text\" name=\"uname\" value=\"\"></td></tr><tr><td>Pass: </td><td><input type=\"password\" name=\"pass\" value=\"\"></td></tr><tr><td>Confirm Pass: </td><td><input type=\"password\" name=\"pass1\" value=\"\"></td></tr><tr><td>First Name: </td><td><input type=\"text\" name=\"fname\" value=\"\"></td></tr><tr><td>Last Name: </td><td><input type=\"text\" name=\"lname\" value=\"\"></td></tr><tr><td>E-mail: </td><td><input type=\"text\" name=\"email\" value=\"\"></td></tr><tr><td>clan: </td><td> <select name=\"clanname\" value=\"\">";$form .= "while($row = mysql_fetch_assoc($result)){ echo '<option value=/"' . htmlspecialchars($row['clanname']) . '/">' . $row['clanname'] . '</option>';}";$form .= "</td></tr><tr><td><input type=\"checkbox\" name=\"emaillist\" value=\"1\"></td><td> If you wouldlike to receive an email informing you of the next tourney check this box.</td></tr><tr><td></td><td>* You must have a clan registered to register as auser.</td></tr><tr><td></table><input type=\"submit\" value=\"submit\" ></form></fieldset>"; Quote Link to comment https://forums.phpfreaks.com/topic/3682-form-as-variable/ Share on other sites More sharing options...
Ge64 Posted February 27, 2006 Share Posted February 27, 2006 [!--quoteo(post=349874:date=Feb 27 2006, 05:42 PM:name=dennisbillings)--][div class=\'quotetop\']QUOTE(dennisbillings @ Feb 27 2006, 05:42 PM) [snapback]349874[/snapback][/div][div class=\'quotemain\'][!--quotec--]I want to make the following form set as a variable I can't get it to work and was hoping someone could give me a hand. The while loop is giving me headaches via parse errors and I can't figure out why. Any help would be greatly appreciated$form .= "<fieldset><form method=\"post\" action=\"<?php echo {$_SERVER['PHP_SELF']};?>\"onsubmit=\"return validate(uname,pass,pass1,fname,lname,email);\"><legend>User Registration: </legend><table><tr><td>Login Name:</td><td> <input type=\"text\" name=\"uname\" value=\"\"></td></tr><tr><td>Pass: </td><td><input type=\"password\" name=\"pass\" value=\"\"></td></tr><tr><td>Confirm Pass: </td><td><input type=\"password\" name=\"pass1\" value=\"\"></td></tr><tr><td>First Name: </td><td><input type=\"text\" name=\"fname\" value=\"\"></td></tr><tr><td>Last Name: </td><td><input type=\"text\" name=\"lname\" value=\"\"></td></tr><tr><td>E-mail: </td><td><input type=\"text\" name=\"email\" value=\"\"></td></tr><tr><td>clan: </td><td> <select name=\"clanname\" value=\"\">";$form .= "while($row = mysql_fetch_assoc($result)){ echo '<option value=/"' . htmlspecialchars($row['clanname']) . '/">' . $row['clanname'] . '</option>';}";$form .= "</td></tr><tr><td><input type=\"checkbox\" name=\"emaillist\" value=\"1\"></td><td> If you wouldlike to receive an email informing you of the next tourney check this box.</td></tr><tr><td></td><td>* You must have a clan registered to register as auser.</td></tr><tr><td></table><input type=\"submit\" value=\"submit\" ></form></fieldset>";[/quote]What errors do you get? It probably doesnt work because you use $form = " ..... "; but you also use " in the HTML. Whenever that happens I use ' instead of " , so like $html = '<div align="center">'; Quote Link to comment https://forums.phpfreaks.com/topic/3682-form-as-variable/#findComment-12759 Share on other sites More sharing options...
kenrbnsn Posted February 27, 2006 Share Posted February 27, 2006 Your code doesn't work because your string has escapes into PHP while you're already in PHP.The question I have for you is why do you want to do this?Here is one solution to your problem:[code]<?php$form .= '<fieldset><form method="post" action="' . $_SERVER['PHP_SELF'] . '"onsubmit="return validate(uname,pass,pass1,fname,lname,email);"><legend>User Registration: </legend><table><tr><td>Login Name:</td><td> <input type="text" name="uname" value=""></td></tr><tr><td>Pass: </td><td><input type="password" name="pass" value=""></td></tr><tr><td>Confirm Pass: </td><td><input type="password" name="pass1" value=""></td></tr><tr><td>First Name: </td><td><input type="text" name="fname" value=""></td></tr><tr><td>Last Name: </td><td><input type="text" name="lname" value=""></td></tr><tr><td>E-mail: </td><td><input type="text" name="email" value=""></td></tr><tr><td>clan: </td><td> <select name="clanname" value="">";while($row = mysql_fetch_assoc($result)){$form .= '<option value="' . htmlspecialchars($row['clanname']) . '">' . $row['clanname'] . '</option>';}$form .= '</td></tr><tr><td><input type="checkbox" name="emaillist" value="1"></td><td> If you wouldlike to receive an email informing you of the next tourney check this box.</td></tr><tr><td></td><td>* You must have a clan registered to register as auser.</td></tr><tr><td></table><input type="submit" value="submit" ></form></fieldset>';?>[/code]Ken Quote Link to comment https://forums.phpfreaks.com/topic/3682-form-as-variable/#findComment-12772 Share on other sites More sharing options...
dennisbillings Posted February 27, 2006 Author Share Posted February 27, 2006 Thanks guys, appreciate the help. Ken to answer your question of why I want to create a form as a variable here it is.I want to validate my form input to make sure the fields are all filled out and the password and confirm password match. [code]IF (isset($_REQUEST["submit"])){ IF (isset($_REQUEST["UserName"])){ $UserName = $_REQUEST["UserName"]; }ELSE{ $message .="You forgot to enter your User Name. /n $form"; }// And the IF else statements will continue to check all the fields and then if there is an error message I don't// want the data to be submitted until the fields are corrected. }ELSE{ $form;[/code]Basically I want the form to appear until the data is submitted correctly. Then the "Thank you for registering statement." and no form. I'm familiar with how to use javascript to check form input and create alerts until the data is correct but I was trying find a way to validate inside of php. I was having trouble figuring out a good way to check the fields and hold sending the data to MySQL until the fields were correct. Quote Link to comment https://forums.phpfreaks.com/topic/3682-form-as-variable/#findComment-12889 Share on other sites More sharing options...
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