Jay2391 Posted February 4, 2007 Share Posted February 4, 2007 I have an array and I am trying to check that if any of the field rank =0 to stop and not continuiing with the code... the issue is that the first record comes 0 but the next is 2 so when it gets the value it overides... how can i stop the while loop and continue with the next code i try end but didn't work while($r_row2 = mysql_fetch_array($r_result2)){ $r_rank2 = $r_row2['rank']; if($r_rank2 == 0){ echo "<br>Tournament is not open for play"; $tournament = FALSE; end(); }else{ $tournament = TRUE; } Quote Link to comment Share on other sites More sharing options...
fert Posted February 4, 2007 Share Posted February 4, 2007 http://us3.php.net/manual/en/control-structures.break.php Quote Link to comment Share on other sites More sharing options...
PC Nerd Posted February 4, 2007 Share Posted February 4, 2007 not sure about this could be completely wrong, but try die(); instead of end(); Quote Link to comment Share on other sites More sharing options...
JasonLewis Posted February 4, 2007 Share Posted February 4, 2007 no... fert has the correct code. you have to use break; die() will simply terminate the script, stop it running whilst break; just breaks you out of the loop. Quote Link to comment Share on other sites More sharing options...
PC Nerd Posted February 4, 2007 Share Posted February 4, 2007 kk. np i missunderstood the QQQ good luck Quote Link to comment Share on other sites More sharing options...
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