Jay2391 Posted February 4, 2007 Share Posted February 4, 2007 I have an array and I am trying to check that if any of the field rank =0 to stop and not continuiing with the code... the issue is that the first record comes 0 but the next is 2 so when it gets the value it overides... how can i stop the while loop and continue with the next code i try end but didn't work while($r_row2 = mysql_fetch_array($r_result2)){ $r_rank2 = $r_row2['rank']; if($r_rank2 == 0){ echo "<br>Tournament is not open for play"; $tournament = FALSE; end(); }else{ $tournament = TRUE; } Link to comment https://forums.phpfreaks.com/topic/36989-stoping-or-if-any-of-array-gives-you-a-number/ Share on other sites More sharing options...
fert Posted February 4, 2007 Share Posted February 4, 2007 http://us3.php.net/manual/en/control-structures.break.php Link to comment https://forums.phpfreaks.com/topic/36989-stoping-or-if-any-of-array-gives-you-a-number/#findComment-176539 Share on other sites More sharing options...
PC Nerd Posted February 4, 2007 Share Posted February 4, 2007 not sure about this could be completely wrong, but try die(); instead of end(); Link to comment https://forums.phpfreaks.com/topic/36989-stoping-or-if-any-of-array-gives-you-a-number/#findComment-176670 Share on other sites More sharing options...
JasonLewis Posted February 4, 2007 Share Posted February 4, 2007 no... fert has the correct code. you have to use break; die() will simply terminate the script, stop it running whilst break; just breaks you out of the loop. Link to comment https://forums.phpfreaks.com/topic/36989-stoping-or-if-any-of-array-gives-you-a-number/#findComment-176683 Share on other sites More sharing options...
PC Nerd Posted February 4, 2007 Share Posted February 4, 2007 kk. np i missunderstood the QQQ good luck Link to comment https://forums.phpfreaks.com/topic/36989-stoping-or-if-any-of-array-gives-you-a-number/#findComment-176685 Share on other sites More sharing options...
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