krixham Posted March 1, 2006 Share Posted March 1, 2006 Now, this code is working, and I am getting the list that I need...[blockquote]<body><?php// Make the connection to MySQL and select the database$conn = mysql_connect;mysql_select_db;$result=mysql_query('SELECT * FROM production_dirs') or die ("Error in query: " .mysql_error());// Close the connection to MySQLmysql_close();echo "<table width='100%'><table style=\"font-family: arial; font-size: 10pt;\">"; $num=mysql_numrows($result);// Start the loop$i=0;while ($i < $num) {// Define your variables// We only want to display the field proj_name for this exercise $proj_name=mysql_result($result,$i,'proj_name');// However we also need the job_name $job_name=mysql_result($result,$i,'job_name');// AND the job directory $projdir=mysql_result($result,$i,'projdir'); echo "<tr> <td>[b][!--coloro:#3366FF--][span style=\"color:#3366FF\"][!--/coloro--]<a href=\"http://172.27.19.36/main.menu.php?$job_name\&$proj_name\&$projdir\" target=clienttype onclick='top.clienttype.location=\"../blank.html\"'> $proj_name \n</a>[!--colorc--][/span][!--/colorc--][/b]</td></tr>";// End loop$i++;}// End tableecho "</table>";echo "</span>";?><!-- Now end the HTML --></body></html>[/blockquote]The problem is happening with the bolded line. Where I am sending the variables on to the next script, and using the clienttype frame on the web page. What I need to do at this point is read another table and the results of that table determine if I go to the clienttype frame or the orderframe, depending on what is in the field 'job_id_name', Thing is right now everything goes right to clienttype. I know this is stupid, but does anyone have any suggestions? For what it's worth, the script that I am trying to kick off is this one:[blockquote]<?php$input = ($_SERVER[argv][0]);$input_array = explode("\&", $input);echo "<pre>";print_r($input_array);echo "</pre>";$client = $ARGV[0];$name = $ARGV[1];$jobdir = $ARGV[2];// Make the connection to MySQL and select the database$conn = mysql_connect;mysql_select_db;// Query your table// In this case we are chosing from the jobinfo TABLE// and are choosing ALL the entries$result=mysql_query('SELECT * FROM jobinfo') or die ("Error in query: " .mysql_error());// Close the connection to MySQLmysql_close();$num=mysql_numrows($result);// We need the job_name $job_name=mysql_result($result,$i,'job_name');// We need the conf_file $conf_file=mysql_result($result,$i,'conf_file');// We need the job_id_name $job_id_name=mysql_result($result,$i,'job_id_name');if($job_id_name = '') { system ("cd $jobdir"); system ("/usr/local/apache2/cgi-bin/order.cgi $client $job_name $conf_file jobdir"); } else { system ("cd $jobdir"); system ("/usr/local/apache2/cgi-bin/choose.cgi $client $name"); print "$jobdir $client\n"; }?>exit 0;[/blockquote]As you can see, I thought of trying to just kick off two seperate scripts. But, it isn't working. Oh, I can see why, I just don't know how to get around it.This was SO much easier just using HTML and static tables. And the MySQL and PHP was my idea 8-( Link to comment https://forums.phpfreaks.com/topic/3852-php-and-html-and-frames/ Share on other sites More sharing options...
php_b34st Posted March 1, 2006 Share Posted March 1, 2006 it depends on how many different options are in the 'job_id_name' field, if there is only a few variations you could use something like:[code]if($job_id_name = 'option1'){ $target = 'clienttype';}else if($job_id_name = 'option2'){ $target = 'orderframe';}echo '<tr> <td><a href="url" target="'.$target.'">'.$proj_name.'</a></td> </tr>';[/code]You can repeat the elseif as many times as you want but if there is a lot of different options you might want to see if there is an easier way than typing lots of else if statements. Link to comment https://forums.phpfreaks.com/topic/3852-php-and-html-and-frames/#findComment-13389 Share on other sites More sharing options...
krixham Posted March 2, 2006 Author Share Posted March 2, 2006 I've been trying and trying and trying to get this to work. I keep telling my boss that I am too stupid to be doing this, but he won't listen <S>.Thank you php_b34st for the input, and I can see where it should work, but for some reason it just isn't doing what I need it to do.There are only two choices under job_id_name - either it is blank or it has something in it. Which is where I am struggling. I need to display the first field based on proj_name, grouped by proj_name, or DISTINCT proj_name.My issue is that I don't quite know the MYSQL commands to get the entire process to do what I need it to do.Back to the old drawing board...Maybe now my boss will believe it?????????????Kathy Link to comment https://forums.phpfreaks.com/topic/3852-php-and-html-and-frames/#findComment-13646 Share on other sites More sharing options...
krixham Posted March 6, 2006 Author Share Posted March 6, 2006 This is now solved, thanks to some information in the topic 'selecting empty columns'. [a href=\"http://www.phpfreaks.com/forums/index.php?showtopic=87617\" target=\"_blank\"]http://www.phpfreaks.com/forums/index.php?showtopic=87617[/a]I appreciate the input I am receiving, and thank everyone for their help.Kathy Link to comment https://forums.phpfreaks.com/topic/3852-php-and-html-and-frames/#findComment-14755 Share on other sites More sharing options...
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