For is not working

[tobeyt23]

Want to display images 2 wide but seems my code breaks the variable up and shows the first 2 letters. What am I doing wrong?

 

<?php
if ($sqldatarow["category"]=="activelife") {
for ($j=0; $j<8; $j++) {
	echo "<tr>\n";
	for ($k=0; $k<2; $k++) {
		$cat = "activelife";
		echo "<td><img src=\"_imgs/galleries/".$cat."/".$sqldatarow['filenamethumb'][$k].".jpg\" class=\"thumb\" alt=\"".$sqldatarow["alt"][$k]."\"></td>\n";
	}
	echo "</tr>\n";
}
} else {
echo "<td> </td>\n";
}

?>

[JBS103]

Sorry, just to clarify... The first two letters of what? The image URL?

[tobeyt23]

it is taken the first 2 letters of the variable filenamethumb

[Orio]

Are you sure $sqldatarow['filenamethumb'] is an array? To me it seems that it is a string. When you do something like this, the $x'th char is outputted:

<?php
$string = "123abc";
$x = 2
echo $string[$x]; //Output- 3
?>

 

Check yourself.

 

Orio.

[JBS103]

It seems to me that $sqldatarow is not a multidimensional array or an array at all, therefore, by you coding $sqldatarow['filenamethumb'][0] and $sqldatarow['filenamethumb'][1], it is taking the first and second characters.

 

I could be wrong so I am hoping someone else could come in and prove it either way, but I think that is how PHP handles a 2nd pair of brackets on a single dimension array.

 

EDIT - Orio got to it.

 

[tobeyt23]

So should i filenamethumb into any array then all 2 at a time that way?